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The following question refers to one mole of chlorine gas. What volume will it occupy at 273°C ?

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Question

The following question refers to one mole of chlorine gas.

What volume will it occupy at 273°C?

Numerical
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Solution

According to Charle's law,

`"V"_2/"T"_2 = "V"_1/"T"_1`

i.e., `"V"_2/(273 + 273) = 22.4/273`

or, V2 = `22.4/273 xx 546`

= 44.8 litres

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Fundamental Laws of Gases - Temperature - Volume Relationship or Charles's Law
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Chapter 5: Mole concept and Stoichiometry - MISCELLANEOUS EXERCISE [Page 96]

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S.P. Singh Concise Chemistry [English] Class 10 ICSE
Chapter 5 Mole concept and Stoichiometry
MISCELLANEOUS EXERCISE | Q 19. (c) | Page 96
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