Advertisements
Advertisements
प्रश्न
88 cm3 of nitrogen is at a pressure of 770 mm mercury. If the pressure is raised to 880 mmHg, find by how much the volume will diminish, the temperature remaining constant.
Advertisements
उत्तर
V = 88 cm3
P = 770 mm
P1 = 880 mm
V1= ?
T = T1
Using gas equation,
`"PV"/"T" = ("P"_1 "V"_1)/"T"_1`
`(770 xx 88)/"T" = (880 xx "V"_1)/"T"`
V1 = 77 cm3
Volume diminishes = 88 - 77 = 11 cm3
APPEARS IN
संबंधित प्रश्न
Explain Charles's law on the basis of the kinetic theory of matter.
State the following:
Ice point in absolute temperature
Choose the correct answer:
The absolute temperature value that corresponds to 27°C is
Choose the correct answer:
The volume-temperature relationship is given by
2 liters of gas is enclosed in a vessel at a pressure of 760 mmHg. If the temperature remains constant, calculate pressure when volume changes to 4 dm3.
State Charles's law.
Correct the following statement:
The volume of a fixed mass of a gas is directly proportional to its temperature, pressure remaining constant.
It is required to reduce the volume of a gas by 20% by compressing it at a constant pressure. To do so, the gas has to be cooled. If the gas attains a final temperature of 157°C, find the initial temperature of the gas.
Fill in the blank with the correct word, from the words in option:
If the temperature of a fixed mass of a gas is kept constant and the pressure is increased, the volume correspondingly _______.
A fixed volume of a gas occupies 760cm3 at 27°C and 70 cm of Hg. What will be its vol. at s.t.p.
