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प्रश्न
A gas at 240 K is heated to 127°C. Find the percentage change in the volume of the gas (pressure remaining constant).
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उत्तर
Let volume = 100 ml
T = 240 K
Volume increased = x ml
New volume = 100 + x ml
T1 = 400 K
Using gas equation,
`"PV"/"T" = ("P"_1 "V"_1)/"T"_1`
`("P" xx 100)/240 = ("P"_1 xx(100 + "x"))/400`
1000 = 6(100 + x)
1000 = 600 + 6x
6x = 400
x = `400/6` = 66.6
Percentage increased = 66.6%
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