Advertisements
Advertisements
प्रश्न
A certain amount of a gas occupies a volume of 0.4 litre at 17°C. To what temperature should it be heated so that its volume gets (a) doubled, (b) reduced to half, pressure remaining constant?
Advertisements
उत्तर
(a) V1 = 0.4 L
V2 = 0.4 × 2L
T1 = 17°C (17 + 273) = 290 K
T2= ?
`("V"_1)/("T"_1) = "V"_2/"T"_2`
`0.4/290 = 0.8/"T"_2`
T2 = 290 x 2 = 580
T2 = 580 - 273 = 307 °C
(b) V1 = 0.4 L
V2 = 0.2 L
T1 = 17°C (17 + 273) = 290 K
T2= ?
`"V"_1/"T"_1 = "V"_2/"T"_2`
`0.4/290 = 0.2/"T"_2`
T2 = `(290 xx 0.2)/0.4 = 145 "K"`
T2 = 145 - 273 = -128 °C
APPEARS IN
संबंधित प्रश्न
Explain Why?
Inflating a balloon seems to violate Boyle's law.
State the law which is represented by the following graph:
Give reasons for the following:
It is necessary to specify the pressure and temperature of gas while stating its volume.
At 0°C and 760 mmHg pressure, a gas occupies a volume of 100 cm3. Kelvin temperature of the gas is increased by one-fifth and the pressure is increased one and a half times. Calculate the final volume of the gas.
22.4 litres of gas weighs 70 g at STP. Calculate the weight of the gas if it occupies a volume of 20 litres at 27°C and 700 mmHg of pressure.
State Boyle’s Law.
Calculate the following:
A gas ‘X’ is collected over water at 17°C and 750 mm. pressure. If the volume of the gas collected is 50 cc., calculate the volume of the dry gas at s.t.p. [at 17°C the vapour pressure is 14 mm.]
Assuming temperature remaining constant calculate the pressure of the gas in the following:
The pressure of a gas having volume 1800 ml. originally occupying 300 ml. at 6 atms. pressure.
Assuming temperature remaining constant calculate the pressure of the gas in the following:
The pressure of a gas having volume 1500 cm3 originally occupying 750 cc. at 5 ats. pressure.
State Boyle’s law
