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Question
A certain amount of a gas occupies a volume of 0.4 litre at 17°C. To what temperature should it be heated so that its volume gets (a) doubled, (b) reduced to half, pressure remaining constant?
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Solution
(a) V1 = 0.4 L
V2 = 0.4 × 2L
T1 = 17°C (17 + 273) = 290 K
T2= ?
`("V"_1)/("T"_1) = "V"_2/"T"_2`
`0.4/290 = 0.8/"T"_2`
T2 = 290 x 2 = 580
T2 = 580 - 273 = 307 °C
(b) V1 = 0.4 L
V2 = 0.2 L
T1 = 17°C (17 + 273) = 290 K
T2= ?
`"V"_1/"T"_1 = "V"_2/"T"_2`
`0.4/290 = 0.2/"T"_2`
T2 = `(290 xx 0.2)/0.4 = 145 "K"`
T2 = 145 - 273 = -128 °C
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State-the law of volume
