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Question
A certain mass of a gas occupies 2 litres at 27°C and 100 Pa. Find the temperature when volume and pressure become half of their initial values.
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Solution
V = 2 litres
P = 100 Pa
T = 300 K
T1 = ?
`"P"1 = 1/2 xx 100 = 50 "Pa"`
`"V"_1 = 1/2 xx 2 = 1 "litre"`
Using gas equation,
`"PV"/"T" = ("P"_1"V"_1)/"T"_1`
`(100xx2)/300 = (50xx1)/"T"_1`
`"T"_1 = 75 "K"`
`"T"_1 = 75 - 273 = -198°C`
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