Advertisements
Advertisements
प्रश्न
A certain mass of a gas occupies 2 litres at 27°C and 100 Pa. Find the temperature when volume and pressure become half of their initial values.
Advertisements
उत्तर
V = 2 litres
P = 100 Pa
T = 300 K
T1 = ?
`"P"1 = 1/2 xx 100 = 50 "Pa"`
`"V"_1 = 1/2 xx 2 = 1 "litre"`
Using gas equation,
`"PV"/"T" = ("P"_1"V"_1)/"T"_1`
`(100xx2)/300 = (50xx1)/"T"_1`
`"T"_1 = 75 "K"`
`"T"_1 = 75 - 273 = -198°C`
APPEARS IN
संबंधित प्रश्न
Explain Why?
Inflating a balloon seems to violate Boyle's law.
Give reasons for the following:
Inflating a balloon seems to violate Boyle's law.
At constant temperature, the effect of change of pressure on the volume of a gas was as given below:
|
Pressure in atmosphere |
Volume in liters |
|
0.20 |
112 |
|
0.25 |
89.2 |
|
0.40 |
56.25 |
|
0.60 |
37.40 |
|
0.80 |
28.10 |
|
1.00 |
22.4 |
(a) Plot the following graphs
- P vs V
- P vs 1/V
- PV vs P
Interpret each graph in terms of the law.
(b) Assuming that the pressure values given above are correct, find the correct measurement of the volume.
561 dm3 of a gas at STP is filled in a 748 dm3 container. If the temperature is constant, calculate the percentage change in pressure required.
State Boyle’s Law.
Correct the following statement:
The volume of a gas is inversely proportional to its pressure at a constant temperature.
A given mass of a gas occupied 143 cm3 at 27° C and 700 mm Hg pressure. What will be its volume at 300 K and 280 mm Hg pressure?
Calculate the volume of a gas ‘A’ at s.t.p., if at 37°C and 775 mm of mercury pressure, it occupies a volume of `9 1/2` litres.
Assuming temperature remaining constant calculate the pressure of the gas in the following:
The pressure of a gas having volume 1000 cc. originally occupying 1500 cc. at 720 mm. pressure.
According to Boyle’s law, the shape of the graph between pressure and reciprocal of volume is _______.
