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प्रश्न
A certain mass of a gas occupies 2 litres at 27°C and 100 Pa. Find the temperature when volume and pressure become half of their initial values.
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उत्तर
V = 2 litres
P = 100 Pa
T = 300 K
T1 = ?
`"P"1 = 1/2 xx 100 = 50 "Pa"`
`"V"_1 = 1/2 xx 2 = 1 "litre"`
Using gas equation,
`"PV"/"T" = ("P"_1"V"_1)/"T"_1`
`(100xx2)/300 = (50xx1)/"T"_1`
`"T"_1 = 75 "K"`
`"T"_1 = 75 - 273 = -198°C`
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संबंधित प्रश्न
At constant temperature, the effect of change of pressure on the volume of a gas was as given below:
|
Pressure in atmosphere |
Volume in liters |
|
0.20 |
112 |
|
0.25 |
89.2 |
|
0.40 |
56.25 |
|
0.60 |
37.40 |
|
0.80 |
28.10 |
|
1.00 |
22.4 |
(a) Plot the following graphs
- P vs V
- P vs 1/V
- PV vs P
Interpret each graph in terms of the law.
(b) Assuming that the pressure values given above are correct, find the correct measurement of the volume.
Calculate the volume occupied by 2 g of hydrogen at 27°C and 4-atmosphere pressure if at STP it occupies 22.4 litres.
Calculate the volume of dry air at STP that occupies 28 cm3 at 14°C and 750 mmHg pressure when saturated with water vapour. The vapour pressure of water at 14°C is 12 mmHg.
State Boyle’s Law.
Give its
(i) mathematical expression
(ii) graphical representation and
(iii) significance.
A given mass of a gas occupied 143 cm3 at 27° C and 700 mm Hg pressure. What will be its volume at 300 K and 280 mm Hg pressure?
Calculate the following:
Calculate the temperature at which a gas ‘A’ at 20°C having a volume, of 500 cc. will occupy a volume of 250 cc.
Assuming temperature remaining constant calculate the pressure of the gas in the following:
The pressure of a gas having volume 100 lits. originally occupying 75 dm3 at 700 mm. pressure.
Assuming temperature remaining constant calculate the pressure of the gas in the following:
The pressure of a gas having volume 1800 ml. originally occupying 300 ml. at 6 atms. pressure.
State-the law of volume
