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प्रश्न
A certain mass of a gas occupies 2 litres at 27°C and 100 Pa. Find the temperature when volume and pressure become half of their initial values.
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उत्तर
V = 2 litres
P = 100 Pa
T = 300 K
T1 = ?
`"P"1 = 1/2 xx 100 = 50 "Pa"`
`"V"_1 = 1/2 xx 2 = 1 "litre"`
Using gas equation,
`"PV"/"T" = ("P"_1"V"_1)/"T"_1`
`(100xx2)/300 = (50xx1)/"T"_1`
`"T"_1 = 75 "K"`
`"T"_1 = 75 - 273 = -198°C`
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संबंधित प्रश्न
Give reasons for the following:
It is necessary to specify the pressure and temperature of gas while stating its volume.
At constant temperature, the effect of change of pressure on the volume of a gas was as given below:
|
Pressure in atmosphere |
Volume in liters |
|
0.20 |
112 |
|
0.25 |
89.2 |
|
0.40 |
56.25 |
|
0.60 |
37.40 |
|
0.80 |
28.10 |
|
1.00 |
22.4 |
(a) Plot the following graphs
- P vs V
- P vs 1/V
- PV vs P
Interpret each graph in terms of the law.
(b) Assuming that the pressure values given above are correct, find the correct measurement of the volume.
State Boyle’s Law.
Correct the following statement:
The volume of a gas is inversely proportional to its pressure at a constant temperature.
Name or state the following:
The law which studies the relationship between pressure of a gas and the volume occupied by it at constant temperature.
Calculate the volume of a gas ‘A’ at s.t.p., if at 37°C and 775 mm of mercury pressure, it occupies a volume of `9 1/2` litres.
Calculate the following:
Calculate the temperature at which a gas ‘A’ at 20°C having a volume, of 500 cc. will occupy a volume of 250 cc.
Calculate the following:
A gas ‘X’ is collected over water at 17°C and 750 mm. pressure. If the volume of the gas collected is 50 cc., calculate the volume of the dry gas at s.t.p. [at 17°C the vapour pressure is 14 mm.]
Assuming temperature remaining constant calculate the pressure of the gas in the following:
The pressure of a gas having volume 1800 ml. originally occupying 300 ml. at 6 atms. pressure.
Calculate the coefficient of cubical expansion of a zinc bar. Whose volume is increased 0.25 m3 from 0.3 m3 due to the change in its temperature of 50K?
