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प्रश्न
State-the law of volume
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उत्तर
According to this law, When the pressure of a gas is kept constant, the volume of a gas is directly proportional to the temperature of the gas.
V ∝ T
(OR)
`"V"/"T"` = constant
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संबंधित प्रश्न
Explain Why?
Inflating a balloon seems to violate Boyle's law.
Give reasons for the following:
It is necessary to specify the pressure and temperature of gas while stating its volume.
At constant temperature, the effect of change of pressure on the volume of a gas was as given below:
|
Pressure in atmosphere |
Volume in liters |
|
0.20 |
112 |
|
0.25 |
89.2 |
|
0.40 |
56.25 |
|
0.60 |
37.40 |
|
0.80 |
28.10 |
|
1.00 |
22.4 |
(a) Plot the following graphs
- P vs V
- P vs 1/V
- PV vs P
Interpret each graph in terms of the law.
(b) Assuming that the pressure values given above are correct, find the correct measurement of the volume.
561 dm3 of a gas at STP is filled in a 748 dm3 container. If the temperature is constant, calculate the percentage change in pressure required.
At 0°C and 760 mmHg pressure, a gas occupies a volume of 100 cm3. Kelvin temperature of the gas is increased by one-fifth and the pressure is increased one and a half times. Calculate the final volume of the gas.
Calculate the volume occupied by 2 g of hydrogen at 27°C and 4-atmosphere pressure if at STP it occupies 22.4 litres.
State Boyle’s Law.
Calculate the volume of a gas ‘A’ at s.t.p., if at 37°C and 775 mm of mercury pressure, it occupies a volume of `9 1/2` litres.
Assuming temperature remaining constant calculate the pressure of the gas in the following:
The pressure of a gas having volume 380 lits. originally occupying 800 cm3 at 76 cm. pressure.
Calculate the coefficient of cubical expansion of a zinc bar. Whose volume is increased 0.25 m3 from 0.3 m3 due to the change in its temperature of 50K?
