Advertisements
Advertisements
प्रश्न
At 0°C and 760 mmHg pressure, a gas occupies a volume of 100 cm3. Kelvin temperature of the gas is increased by one-fifth and the pressure is increased one and a half times. Calculate the final volume of the gas.
Advertisements
उत्तर
V = 100 cm3
P = 760 mm
T = 273 K
V1= ?
`"T"_1 = 273 xx 1/5 = 54.6 = 273 + 54.6 = 327.6 "K"`
`"P"_1 = 1 1/2 xx 760 = 760 xx 3/2 = 1140` mm
V1 = ?
Using gas equation,
`"PV"/"T" = ("P"_1"V"_1)/"T"_1`
`(760xx100)/273 = (1140 xx "V"_1)/327.6`
V1 = 80 cm3
APPEARS IN
संबंधित प्रश्न
Give reasons for the following:
Inflating a balloon seems to violate Boyle's law.
A certain amount of a gas occupies a volume of 0.4 litre at 17°C. To what temperature should it be heated so that its volume gets (a) doubled, (b) reduced to half, pressure remaining constant?
State Boyle’s Law.
Correct the following statement:
The volume of a gas is inversely proportional to its pressure at a constant temperature.
50 cm3 of hydrogen is collected over water at 17°C and 750 mmHg pressure. Calculate the volume of a dry gas at STP. The water vapour pressure at 17°C is 14 mmHg.
Calculate the volume of a gas ‘A’ at s.t.p., if at 37°C and 775 mm of mercury pressure, it occupies a volume of `9 1/2` litres.
Assuming temperature remaining constant calculate the pressure of the gas in the following:
The pressure of a gas having volume 1000 cc. originally occupying 1500 cc. at 720 mm. pressure.
Fill in the blank with the correct word, from the words in option:
If the pressure of a fixed mass of a gas is kept constant and the temperature is increased, the volume correspondingly _______
According to Boyle’s law, the shape of the graph between pressure and reciprocal of volume is _______.
State Boyle’s law
