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प्रश्न
50 cm3 of hydrogen is collected over water at 17°C and 750 mmHg pressure. Calculate the volume of a dry gas at STP. The water vapour pressure at 17°C is 14 mmHg.
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उत्तर
V = 50 cm3
P = 750 - 14 = 736 mm
T = 290 K
P1 = 760 mm
V1= ?
T1 = 273 K
Using gas equation,
`("P" "V")/"T" = ("P"_1 "V"_1)/"T"_1`
`(736 xx 50)/290 = (760 xx "V"_1)/273`
`"V"_1 = 45.6 "cm"^3`
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संबंधित प्रश्न
Explain Boyle's Law on the basis of the kinetic theory of matter.
At constant temperature, the effect of change of pressure on the volume of a gas was as given below:
|
Pressure in atmosphere |
Volume in liters |
|
0.20 |
112 |
|
0.25 |
89.2 |
|
0.40 |
56.25 |
|
0.60 |
37.40 |
|
0.80 |
28.10 |
|
1.00 |
22.4 |
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- P vs V
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- PV vs P
Interpret each graph in terms of the law.
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Give its
(i) mathematical expression
(ii) graphical representation and
(iii) significance.
Assuming temperature remaining constant calculate the pressure of the gas in the following:
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Fill in the blank with the correct word, from the words in option:
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