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प्रश्न
561 dm3 of a gas at STP is filled in a 748 dm3 container. If the temperature is constant, calculate the percentage change in pressure required.
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उत्तर
Initial volume = V1 = 561 dm3
Final volume = V2 = 748 dm3
Difference in volume = 748 - 561 = 187 dm3
As the temperature is constant,
Decrease in pressure percentage = `187/748 xx 100 = 25%`
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संबंधित प्रश्न
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Inflating a balloon seems to violate Boyle's law.
Give reasons for the following:
It is necessary to specify the pressure and temperature of gas while stating its volume.
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|
Pressure in atmosphere |
Volume in liters |
|
0.20 |
112 |
|
0.25 |
89.2 |
|
0.40 |
56.25 |
|
0.60 |
37.40 |
|
0.80 |
28.10 |
|
1.00 |
22.4 |
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