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प्रश्न
561 dm3 of a gas at STP is filled in a 748 dm3 container. If the temperature is constant, calculate the percentage change in pressure required.
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उत्तर
Initial volume = V1 = 561 dm3
Final volume = V2 = 748 dm3
Difference in volume = 748 - 561 = 187 dm3
As the temperature is constant,
Decrease in pressure percentage = `187/748 xx 100 = 25%`
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संबंधित प्रश्न
At constant temperature, the effect of change of pressure on the volume of a gas was as given below:
|
Pressure in atmosphere |
Volume in liters |
|
0.20 |
112 |
|
0.25 |
89.2 |
|
0.40 |
56.25 |
|
0.60 |
37.40 |
|
0.80 |
28.10 |
|
1.00 |
22.4 |
(a) Plot the following graphs
- P vs V
- P vs 1/V
- PV vs P
Interpret each graph in terms of the law.
(b) Assuming that the pressure values given above are correct, find the correct measurement of the volume.
A certain mass of a gas occupies 2 litres at 27°C and 100 Pa. Find the temperature when volume and pressure become half of their initial values.
Calculate the volume occupied by 2 g of hydrogen at 27°C and 4-atmosphere pressure if at STP it occupies 22.4 litres.
State Boyle’s Law.
A given mass of a gas occupied 143 cm3 at 27° C and 700 mm Hg pressure. What will be its volume at 300 K and 280 mm Hg pressure?
A gas cylinder having a capacity of 20 litres contains a gas at 100 atmos. How many flasks of 200 cm3 capacity can be filled from it at 1 atmos. pressure if the temperature remains constant?
Name or state the following:
The law which studies the relationship between pressure of a gas and the volume occupied by it at constant temperature.
Assuming temperature remaining constant calculate the pressure of the gas in the following:
The pressure of a gas having volume 100 lits. originally occupying 75 dm3 at 700 mm. pressure.
Assuming temperature remaining constant calculate the pressure of the gas in the following:
The pressure of a gas having volume 380 lits. originally occupying 800 cm3 at 76 cm. pressure.
Calculate the coefficient of cubical expansion of a zinc bar. Whose volume is increased 0.25 m3 from 0.3 m3 due to the change in its temperature of 50K?
