Advertisements
Advertisements
प्रश्न
561 dm3 of a gas at STP is filled in a 748 dm3 container. If the temperature is constant, calculate the percentage change in pressure required.
Advertisements
उत्तर
Initial volume = V1 = 561 dm3
Final volume = V2 = 748 dm3
Difference in volume = 748 - 561 = 187 dm3
As the temperature is constant,
Decrease in pressure percentage = `187/748 xx 100 = 25%`
APPEARS IN
संबंधित प्रश्न
State the law which is represented by the following graph:

A steel cylinder of internal volume 20 litres is filled with hydrogen at 29 atmospheric pressure. If hydrogen is used to fill a balloon at 1.25 atmospheric pressure at the same temperature, what volume will the gas occupy?
A certain amount of a gas occupies a volume of 0.4 litre at 17°C. To what temperature should it be heated so that its volume gets (a) doubled, (b) reduced to half, pressure remaining constant?
Calculate the volume of dry air at STP that occupies 28 cm3 at 14°C and 750 mmHg pressure when saturated with water vapour. The vapour pressure of water at 14°C is 12 mmHg.
State Boyle’s Law.
Give its
(i) mathematical expression
(ii) graphical representation and
(iii) significance.
Correct the following statement:
The volume of a gas is inversely proportional to its pressure at a constant temperature.
A gas cylinder having a capacity of 20 litres contains a gas at 100 atmos. How many flasks of 200 cm3 capacity can be filled from it at 1 atmos. pressure if the temperature remains constant?
Assuming temperature remaining constant calculate the pressure of the gas in the following:
The pressure of a gas having volume 1800 ml. originally occupying 300 ml. at 6 atms. pressure.
State Boyle’s law
