Advertisements
Advertisements
Question
A given mass of a gas occupied 143 cm3 at 27° C and 700 mm Hg pressure. What will be its volume at 300 K and 280 mm Hg pressure?
Advertisements
Solution
V1 = 143 cm3
T1 = 27 C = 27+273 = 300 K
P1 = 700 mm Hg
T2 = 300 K
P2 = 280 mm Hg
V2 = ?
`therefore ("P"_1 "V"_1)/"T"_1 = ("P"_2 "V"_2)/"T"_2`
`therefore (700xx143)/300 = (280xx"V"_2)/300`
`therefore (700 xx 143 xx 300)/(300 xx 280)` = V2
`therefore "V"_2 = 357.5 " cm"^3`
APPEARS IN
RELATED QUESTIONS
Give reasons for the following:
Inflating a balloon seems to violate Boyle's law.
Give reasons for the following:
It is necessary to specify the pressure and temperature of gas while stating its volume.
561 dm3 of a gas at STP is filled in a 748 dm3 container. If the temperature is constant, calculate the percentage change in pressure required.
Give its
(i) mathematical expression
(ii) graphical representation and
(iii) significance.
Correct the following statement:
The volume of a gas is inversely proportional to its pressure at a constant temperature.
Assuming temperature remaining constant calculate the pressure of the gas in the following:
The pressure of a gas having volume 1000 cc. originally occupying 1500 cc. at 720 mm. pressure.
Assuming temperature remaining constant calculate the pressure of the gas in the following:
The pressure of a gas having volume 100 lits. originally occupying 75 dm3 at 700 mm. pressure.
Assuming temperature remaining constant calculate the pressure of the gas in the following:
The pressure of a gas having volume 1800 ml. originally occupying 300 ml. at 6 atms. pressure.
Fill in the blank with the correct word, from the words in option:
If the pressure of a fixed mass of a gas is kept constant and the temperature is increased, the volume correspondingly _______
State Boyle’s law
