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प्रश्न
Calculate the volume of dry air at STP that occupies 28 cm3 at 14°C and 750 mmHg pressure when saturated with water vapour. The vapour pressure of water at 14°C is 12 mmHg.
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उत्तर
Pressure due to dry air,
P = 750 - 12 = 738 mm
V = 28 cm3
T = 14°C = 14 + 273 = 287 K
P1 = 760 mmHg
V1= ?
T1 = 0°C = 273 K
Using gas equation,
`("P" "V")/"T" = ("P"_1 "V"_1)/"T"_1`
`(738xx28)/287 = (760xx"V"_1)/273`
`"V"_1 = 25.9 "cm"^3`
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संबंधित प्रश्न
Give reasons for the following:
It is necessary to specify the pressure and temperature of gas while stating its volume.
Choose the correct answer:
If the pressure is doubled for a fixed mass of a gas, its volume will become
At constant temperature, the effect of change of pressure on the volume of a gas was as given below:
|
Pressure in atmosphere |
Volume in liters |
|
0.20 |
112 |
|
0.25 |
89.2 |
|
0.40 |
56.25 |
|
0.60 |
37.40 |
|
0.80 |
28.10 |
|
1.00 |
22.4 |
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- P vs V
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- PV vs P
Interpret each graph in terms of the law.
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State Boyle’s Law.
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The volume of a gas is inversely proportional to its pressure at a constant temperature.
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Calculate the temperature at which a gas ‘A’ at 20°C having a volume, of 500 cc. will occupy a volume of 250 cc.
Assuming temperature remaining constant calculate the pressure of the gas in the following:
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