Question

State Charles's law.

Answer 1

Charles's Law

At constant pressure, the volume of a given mass of a dry gas increases or decreases by 1/273^rd of its original volume at 0°C for each degree centigrade rise or fall in temperature.

V ∝ T (at constant pressure)
At temperature T₁ (K) and volume V₁ (cm³):

`"V"_1 ∝ "T"_1 "or" "V"_1/"T"_1 = "K"` = constant...(i)

At temperature T₂ (K) and volume V₂ (cm³):

`"V"_2 ∝ "T"_2 "or" "V"_2/"T"_2 = "K"` = constant….(ii)

From (i) and (ii),

`"V"_1/"T"_1 = "V"_2/"T"_2` = constant

For Temperature = Conversion from Celsius to Kelvin

1 K = °C + 273

Example:

20°C = 20 + 273 = 293 K