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Question
A fixed volume of a gas occupies 760cm3 at 27°C and 70 cm of Hg. What will be its vol. at s.t.p.
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Solution
P1 = 70 CM OF Hg
V1 = 760 cm3
T1 = 27°C
P2 = 76 cm of Hg
V2 = ?
T2 = 273 K
Using the gas equation, `("P"_1"V"_1)/"T"_1 = ("P"_2"V"_2)/"T"_2`
`= (70 xx 760)/300 = (76 xx "V"_2)/273`
∴ V2 = `(70xx760xx273)/(300xx76) = 637`cm3
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