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Question
Solve the following :
Find the cartesian equation of the plane passing through A(1,-2, 3) and direction ratios of whose normal are 0, 2, 0.
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Solution
The Cartesian equation of the plane passing through (x1, y1, z1), the direction ratios of whose normal are a, b, c, is
a(x – x1) + b(y – y1) + c(z – z1) = 0
∴ the cartesian equation of the required plane is
0(x + 1) + 2(y + 2) + 0(z – 3) = 0
∴ 2y + 4 = 0
dividing equation by 2
`(2y+4)/2 =0/2`
∴ y + 2 = 0
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