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Question
A line passes through (3, –1, 2) and is perpendicular to lines `bar"r" = (hat"i" + hat"j" - hat"k") + lambda(2hat"i" - 2hat"j" + hat"k") and bar"r" = (2hat"i" + hat"j" - 3hat"k") + mu(hat"i" - 2hat"j" + 2hat"k")`. Find its equation.
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Solution
The line `bar"r" = (hat"i" + hat"j" - hat"k") + λ(2hat"i" - 2hat"j" + hat"k")` is parallel to the vector `bar"b" = 2hat"i" - 2hat"j" + hat"k"` and the line `bar"r" = (2hat"i" + hat"j" - 3hat"k") + mu(hat"i" - 2hat"j" + 2hat"k")` is parallel to the vector. `bar"c" = hat"i" - 2hat"j" + 2hat"k"`.
The vector perpendicular to the vectors `bar"b" and bar"c"` is given by
`bar"b" xx bar"c" = |(hat"i" hatj hatk), (2 -2 1),(1 -2 2)|`
`= hat"i"(-4 + 2) - hat"j"(4 - 1) + hat"k"(-4 + 2)`
`= -2hat"i" - 3hat"j" - 2hat"k"`
Since the required line is perpendicular to the given lines,
it is perpendicular to both `bar"b" and bar"c"`.
∴ It is parallel to `bar"b" xx bar"c"`
The equation of the line passing through `"A"(bara)` and parallel to `bar"b" and bar"c"` is
`bar"r" = bar"a" + λ(bar"b" xx bar"c")`, where λ is a scalar.
Here, `bar"a" = 3hat"i" - hat"j" + 2hat"k"`
∴ the equation of the required line is
`bar"r" = (3hat"i" - hat"j" + 2hat"k") + λ(-2hat"i" - 3hat"j" - 2hat"k")`
or
`bar"r" = (3hat"i" - hat"j" + 2hat"k") + mu(2hat"i" + 3hat"j" + 2hat"k")`, where μ = `-λ`.
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