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Show that F(X) = X2 − X Sin X is an Increasing Function on (0, π/2) ?

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Question

Show that f(x) = x2 − x sin x is an increasing function on (0, π/2) ?

Sum
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Solution

\[f\left( x \right) = x^2 - x \sin x\]

\[f'\left( x \right) = 2x - x \cos x - \sin x\]

\[\text { Here,} \]

\[0 < x < \frac{\pi}{2}\]

\[ \Rightarrow 0 < \sin x < 1 \text { and }0 < \cos x < 1\]

\[ \Rightarrow 2x - x \cos x - \sin x > 0\]

\[ \Rightarrow f'\left( x \right) > 0, \forall x \in \left( 0, \frac{\pi}{2} \right)\]

\[\text { So },f\left( x \right)\text {  is increasing on}\left( 0, \frac{\pi}{2} \right).\]

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Chapter 16: Increasing and Decreasing Functions - Exercise 17.2 [Page 35]

APPEARS IN

R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 16 Increasing and Decreasing Functions
Exercise 17.2 | Q 34 | Page 35

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