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Find the value of x, such that f(x) is increasing function. f(x) = 2x3 - 15x2 + 36x + 1

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Question

Find the value of x, such that f(x) is increasing function.

f(x) = 2x3 - 15x2 + 36x + 1 

Sum
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Solution

f(x) = 2x3 - 15x2 + 36x + 1 

∴ f'(x) = 6x2 - 30x + 36

= 6(x2 - 5x + 6)

= 6(x - 3)(x - 2)

f(x) is an increasing function, if f'(x) > 0

∴ 6(x - 3)(x - 2) > 0

∴ (x - 3)(x - 2) > 0

ab > 0 ⇔ a > 0 and b > 0 or a < 0 or b < 0

∴ Either (x – 3) > 0 and (x – 2) > 0 or
(x – 3) < 0 and (x – 2) < 0

Case 1: x – 3 > 0    and    x – 2 > 0

∴ x > 3       and      x > 2

∴ x > 3

Case 2: x – 3 < 0     and      x – 2 < 0

∴ x < 3       and      x < 2

∴ x < 2

Thus, f(x) is an increasing function for x < 2 or x > 3, i.e., (- ∞, 2) ∪ (3, ∞)

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Chapter 4: Applications of Derivatives - Exercise 4.2 [Page 106]

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Balbharati Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
Chapter 4 Applications of Derivatives
Exercise 4.2 | Q 2.1 | Page 106

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