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In the Interval (1, 2), Function F(X) = 2 | X − 1 | + 3 | X − 2 | is - Mathematics

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Question

In the interval (1, 2), function f(x) = 2 | x − 1 | + 3 | x − 2 | is

Options

  • increasing

  • decreasing

  • constant

  • none of these

MCQ
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Solution

 decreasing

\[\text { Given }: f\left( x \right) = 2\left| x - 1 \right| + 3\left| x - 2 \right|\]

\[\text { If 1 < x < 2, then }\left| x - 1 \right| = x - 1 . \]

\[ \Rightarrow \left| x - 2 \right| = - \left( x - 2 \right)\]

\[\text { Now,}\]

\[f\left( x \right) = 2\left| x - 1 \right| + 3\left| x - 2 \right|\]

\[ = 2 \left( x - 1 \right) + 3 \left( - x + 2 \right)\]

\[ = 2x - 2 - 3x + 6\]

\[ = - x + 4\]

\[f'\left( x \right) = - 1 < 0\]

\[\text { So,}f\left( x \right) \text { is decreasing when 1 < x < 2 } .\]

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Chapter 17: Increasing and Decreasing Functions - Exercise 17.4 [Page 41]

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RD Sharma Mathematics [English] Class 12
Chapter 17 Increasing and Decreasing Functions
Exercise 17.4 | Q 20 | Page 41

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