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Find the intervals in which the following functions are strictly increasing or decreasing: −2x3 − 9x2 − 12x + 1 - Mathematics

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Question

Find the intervals in which the following functions are strictly increasing or decreasing:

−2x3 − 9x2 − 12x + 1

Sum
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Solution

f(x) = - 2x3 - 9x2 - 12x + 1

f'(x) = -6x2 - 18x - 12 = - 6(x2 + 3x + 2)

= - 6(x + 2)(x + 1)

If f'(x) = 0

-6(x + 2)(x + 1) = 0

x = - 2, -1 divides the real line into three intervals: `(- infty, -2), (-2, -1)` and `(-1, infty)`.

The function f is continuously increasing in the intervals `(- infty, -2)` and `(-1, infty)` and continuously decreasing in (-2, -1).

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Chapter 6: Application of Derivatives - Exercise 6.2 [Page 205]

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NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 6 Application of Derivatives
Exercise 6.2 | Q 6.3 | Page 205

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