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Show That F(X) = Cos2 X Is a Decreasing Function on (0, π/2) ?

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Question

Show that f(x) = cos2 x is a decreasing function on (0, π/2) ?

Sum
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Solution

\[f\left( x \right) = \cos^2 x\]

\[f'\left( x \right) = 2 \cos x \left( - \sin x \right)\]

\[ \Rightarrow f'\left( x \right) = - \sin \left( 2x \right) . . . \left( 1 \right)\]

\[\text { Now,}\]

\[0 < x < \frac{\pi}{2}\]

\[ \Rightarrow 0 < 2x < \pi \]

\[ \Rightarrow \sin 2x > 0 \left[ \because \text { Sine fuction is positive in first and second quadrant } \right]\]

\[ \Rightarrow - \sin 2x < 0\]

\[ \Rightarrow f'\left( x \right) < 0 \left[ \text { From eq.} (1) \right]\]

\[\text { So,f(x)is decreasing on}\left( 0, \frac{\pi}{2} \right).\]

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Chapter 16: Increasing and Decreasing Functions - Exercise 17.2 [Page 34]

APPEARS IN

R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 16 Increasing and Decreasing Functions
Exercise 17.2 | Q 11 | Page 34

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