Advertisements
Advertisements
Question
sec2θ − cos2θ = tan2θ + sin2θ हे सिद्ध करा.
Sum
Advertisements
Solution
डावी बाजू = sec2θ − cos2θ
= 1 + tan2θ – cos2θ .......[∵ 1 + tan2θ = sec2θ]
= tan2θ + (1 – cos2θ)
= tan2θ + sin2θ ......`[(because sin^2theta +cos^2theta = 1),(therefore 1 - cos^2theta = sin^2theta)]`
= उजवी बाजू
∴ sec2θ − cos2θ = tan2θ + sin2θ
shaalaa.com
त्रिकोणमितीय नित्यसमानता
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
cot θ + tan θ = cosec θ sec θ
sec4θ - cos4θ = 1 - 2cos2θ
secθ + tanθ = `cosθ/(1 - sinθ)`
sinθ × cosecθ = किती?
`tanθ/(secθ + 1) = (secθ - 1)/tanθ`
sec2θ + cosec2θ = sec2θ × cosec2θ हे सिद्ध करा.
`costheta/(1 + sintheta) = (1 - sintheta)/(costheta)` हे सिद्ध करा.
जर sec θ = `41/40`, तर sin θ, cot θ, cosec θ च्या किमती काढा.
sin4A – cos4A = 1 – 2cos2A हे सिद्ध करा.
2(sin6A + cos6A) – 3(sin4A + cos4A) + 1 = 0 हे सिद्ध करा.
