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Maharashtra State BoardSSC (English Medium) 10th Standard

Prove that tan(90-θ)+cot(90-θ)cosecθ = sec θ - Geometry Mathematics 2

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Question

Prove that `(tan(90 - theta) + cot(90 - theta))/("cosec"  theta)` = sec θ

Sum
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Solution

L.H.S = `(tan(90 - theta) + cot(90 - theta))/("cosec"  theta)`

= `1/("cosec"  theta)(cottheta + tantheta)`  .....`[(because tan(90 - theta) = cot theta),(cot(90 - theta) = tantheta)]`

= sin θ (cot θ + tan θ)

= `sintheta ((costheta)/(sintheta) + (sintheta)/(costheta))`

= `sintheta ((cos^2theta + sin^2theta)/(sintheta costheta))`

= `sintheta (1/(sintheta costheta))`   ......[∵ sin2θ  + cos2θ = 1]

= `1/costheta`

= sec θ

= R.H.S

∴ `(tan(90 - theta) + cot(90 - theta))/("cosec"  theta)` = sec θ

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Chapter 6: Trigonometry - Q.3 (B)

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