Question

If x =  a sin θ and y = bcos θ , write the value of`(b^2 x^2 + a^2 y^2)`

Answer 1

`(b^2 x^2 + a^2 y^2)`

=`b^2 (a sin theta )^2 + a^2 ( bcos theta)^2`

=`b^2 a^2 sin^2 theta + a^2 b^2 cos^2 theta`

=`a^2 b^2 ( sin^2 theta + cos ^2 theta)`

=`a^2 b^2 (1)`

=`a^2 b^2`