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Questions
`1 + (tan^2 θ)/((1 + sec θ)) = sec θ`
Prove the following:
`1 + (tan^2 θ)/(1 + sec θ) = sec θ`
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Solution
LHS = `1 + (tan^2 θ)/((1 + sec θ))`
=` 1 + ((sec^2 θ - 1))/((sec theta + 1))`
=`1 + ((sec theta + 1)(sec theta - 1))/((sec theta + 1))`
=`1 + (sec theta - 1)`
= sec θ
LHS = RHS
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