English
Maharashtra State BoardSSC (English Medium) 10th Standard

If tan θ × A = sin θ, then A = ?

Advertisements
Advertisements

Question

If tan θ × A = sin θ, then A = ?

Sum
Advertisements

Solution

tan θ × A = sin θ   ...[Given]

∴ `(sin θ)/(cos θ) xx A = sin θ`

∴`1/(cos θ) xx A = 1`

∴ A = cos θ

shaalaa.com
  Is there an error in this question or solution?
Chapter 6: Trigonometry - Exercise

RELATED QUESTIONS

 

Evaluate

`(sin ^2 63^@ + sin^2 27^@)/(cos^2 17^@+cos^2 73^@)`

 

Prove the following trigonometric identities.

`(1 - sin θ)/(1 + sin θ) = (sec θ - tan θ)^2`


Prove the following trigonometric identities.

(sec A − cosec A) (1 + tan A + cot A) = tan A sec A − cot A cosec A


Prove the following identities:

sec2A + cosec2A = sec2A . cosec2A


`(sec theta + tan theta )/( sec theta - tan theta ) = ( sec theta + tan theta )^2 = 1+2 tan^2 theta + 25 sec theta tan theta `


`(1+ cos theta + sin theta)/( 1+ cos theta - sin theta )= (1+ sin theta )/(cos theta)`


If tan A = n tan B and sin A = m sin B , prove that  `cos^2 A = ((m^2-1))/((n^2 - 1))`


Write the value of cos1° cos 2°........cos180° .


Prove that:

`"tanθ"/("secθ"  –  1) = (tanθ + secθ + 1)/(tanθ + secθ - 1)`


If \[\sin \theta = \frac{1}{3}\] then find the value of 9tan2 θ + 9. 


Prove the following identity :

`tanA - cotA = (1 - 2cos^2A)/(sinAcosA)`


If sinA + cosA = `sqrt(2)` , prove that sinAcosA = `1/2`


Prove that (sin θ + cosec θ)2 + (cos θ + sec θ)2 = 7 + tanθ + cotθ. 


Prove that:
`sqrt(( secθ - 1)/(secθ + 1)) + sqrt((secθ + 1)/(secθ - 1)) = 2 "cosec"θ`


If x = a sec θ + b tan θ and y = a tan θ + b sec θ prove that x2 - y2 = a2 - b2.


Prove that (cosec A - sin A)( sec A - cos A) sec2 A = tan A.


`sin θ = 1/2`, then θ = ?


Prove that `(tan(90 - θ) + cot(90 - θ))/("cosec"  θ) = sec θ`.


Prove the following:

`1 + (cot^2 alpha)/(1 + "cosec"  alpha)` = cosec α


Let α, β be such that π < α – β < 3π. If sin α + sin β = `-21/65` and cos α + cos β = `-27/65`, then the value of `cos  (α - β)/2` is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×