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Prove That: Cos 55° + Cos 65° + Cos 175° = 0

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Question

Prove that:
 cos 55° + cos 65° + cos 175° = 0

Sum
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Solution

Consider LHS: 
\[\cos 55^\circ + \cos 65^\circ + \cos 175^\circ\]
\[ = 2\cos \left( \frac{55^\circ + 65^\circ}{2} \right) \cos \left( \frac{55^\circ - 65^\circ}{2} \right) + \cos 175^\circ \left\{ \because \cos A + \cos B = 2\cos\left( \frac{A + B}{2} \right)\cos\left( \frac{A - B}{2} \right) \right\}\]
\[ = 2\cos 60^\circ \cos\left( - 5^\circ \right) + \cos 175^\circ\]
\[ = 2 \times \frac{1}{2}\cos 5^\circ + \cos 175^\circ\]
\[ = \cos 5^\circ + \cos 175^\circ\]
\[ = 2\cos \left( \frac{5^\circ + 175^\circ}{2} \right) \cos \left( \frac{5^\circ - 175^\circ}{2} \right)\]
\[ = 2\cos 90^\circ \cos 85^\circ\]
\[ = 0\]
Hence, LHS = RHS.

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Transformation Formulae
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Chapter 8: Transformation formulae - Exercise 8.2 [Page 17]

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R.D. Sharma Mathematics [English] Class 11
Chapter 8 Transformation formulae
Exercise 8.2 | Q 3.1 | Page 17

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