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If (Cos α + Cos β)2 + (Sin α + Sin β)2 = λ Cos 2 ( α − β 2 ) , Write the Value of λ.

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Question

If (cos α + cos β)2 + (sin α + sin β)2 = \[\lambda \cos^2 \left( \frac{\alpha - \beta}{2} \right)\], write the value of λ. 

Sum
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Solution

(cos α + cos β)2 + (sin α + sin β)2 = \[\lambda \cos^2 \left( \frac{\alpha - \beta}{2} \right)\] 

Consider LHS:
(cos α + cos β)2 + (sin α + sin β)2

\[= \left[ 2\cos \left( \frac{\alpha + \beta}{2} \right) cos \left( \frac{\alpha - \beta}{2} \right) \right]^2 + \left[ 2\sin \left( \frac{\alpha + \beta}{2} \right) \cos \left( \frac{\alpha - \beta}{2} \right) \right]^2 \]
\[ = 4 \cos^2 \left( \frac{\alpha + \beta}{2} \right) \cos^2 \left( \frac{\alpha - \beta}{2} \right) + 4 \sin^2 \left( \frac{\alpha + \beta}{2} \right) \cos^2 \left( \frac{\alpha - \beta}{2} \right)\]
\[ = 4 \cos^2 \left( \frac{\alpha - \beta}{2} \right)\left[ \cos^2 \left( \frac{\alpha + \beta}{2} \right) + \sin^2 \left( \frac{\alpha + \beta}{2} \right) \right]\]
\[ = 4 \cos^2 \left( \frac{\alpha - \beta}{2} \right)\]
 = RHS

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Transformation Formulae
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Chapter 8: Transformation formulae - Exercise 8.3 [Page 20]

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R.D. Sharma Mathematics [English] Class 11
Chapter 8 Transformation formulae
Exercise 8.3 | Q 1 | Page 20

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