English

If Tan α = X X + 1 and Tan β = 1 2 X + 1 , Then Tan β = 1 2 X + 1 is Equal to

Advertisements
Advertisements

Question

If \[\tan\alpha = \frac{x}{x + 1}\] and 

\[\tan\beta = \frac{1}{2x + 1}\], then
\[\tan\beta = \frac{1}{2x + 1}\] is equal to

 

Options

  • \[\frac{\pi}{2}\]

     

  • \[\frac{\pi}{2}\]

     

  • \[\frac{\pi}{2}\]

     

  • \[\frac{\pi}{2}\]

     

MCQ
Sum
Advertisements

Solution

It is given that \[\tan\alpha = \frac{x}{x + 1}\] and \[\tan\beta = \frac{x}{x + 1}\] 

Now,
\[\tan\left( \alpha + \beta \right) = \frac{\tan\alpha + \tan\beta}{1 - \tan\alpha \tan\beta}\]
\[ = \frac{\frac{x}{x + 1} + \frac{1}{2x + 1}}{1 - \frac{x}{x + 1} \times \frac{1}{2x + 1}}\]
\[ = \frac{\frac{x\left( 2x + 1 \right) + x + 1}{\left( x + 1 \right)\left( 2x + 1 \right)}}{\frac{\left( x + 1 \right)\left( 2x + 1 \right) - x}{\left( x + 1 \right)\left( 2x + 1 \right)}}\]
\[ = \frac{2 x^2 + x + x + 1}{2 x^2 + 3x + 1 - x}\]
\[= \frac{2 x^2 + 2x + 1}{2 x^2 + 2x + 1}\]
\[ = 1\]
\[\therefore \tan\left( \alpha + \beta \right) = 1 = \tan\frac{\pi}{4}\]
\[ \Rightarrow \alpha + \beta = \frac{\pi}{4}\]

Hence, the correct answer is option D.

shaalaa.com
Transformation Formulae
  Is there an error in this question or solution?
Chapter 8: Transformation formulae - Exercise 8.4 [Page 22]

APPEARS IN

R.D. Sharma Mathematics [English] Class 11
Chapter 8 Transformation formulae
Exercise 8.4 | Q 14 | Page 22

RELATED QUESTIONS

Prove that:

\[2\cos\frac{5\pi}{12}\cos\frac{\pi}{12} = \frac{1}{2}\]

Show that :

\[\sin 25^\circ \cos 115^\circ = \frac{1}{2}\left( \sin 140^\circ - 1 \right)\]

\[\text{ Prove that }4 \cos x \cos\left( \frac{\pi}{3} + x \right) \cos \left( \frac{\pi}{3} - x \right) = \cos 3x .\]

 


Prove that:
cos 40° cos 80° cos 160° = \[- \frac{1}{8}\]

 


Prove that:
 sin 20° sin 40° sin 80° = \[\frac{\sqrt{3}}{8}\]

 


Prove that:
sin 10° sin 50° sin 60° sin 70° = \[\frac{\sqrt{3}}{16}\]

 


Show that:
sin (B − C) cos (A − D) + sin (C − A) cos (B − D) + sin (A − B) cos (C − D) = 0


Express each of the following as the product of sines and cosines:
sin 12x + sin 4x


Express each of the following as the product of sines and cosines:
 cos 12x + cos 8x


Express each of the following as the product of sines and cosines:
 cos 12x - cos 4x


Express each of the following as the product of sines and cosines:
sin 2x + cos 4x


Prove that:
 sin 50° − sin 70° + sin 10° = 0



Prove that:
\[\sin\frac{5\pi}{18} - \cos\frac{4\pi}{9} = \sqrt{3} \sin\frac{\pi}{9}\]


Prove that:

\[\cos\frac{\pi}{12} - \sin\frac{\pi}{12} = \frac{1}{\sqrt{2}}\]

 


Prove that:

sin 80° − cos 70° = cos 50°

Prove that:

\[\cos\left( \frac{\pi}{4} + x \right) + \cos\left( \frac{\pi}{4} - x \right) = \sqrt{2} \cos x\]

 


Prove that:

\[\sin 65^\circ + \cos 65^\circ = \sqrt{2} \cos 20^\circ\]

Prove that:
sin 3A + sin 2A − sin A = 4 sin A cos \[\frac{A}{2}\] \[\frac{3A}{2}\]

 


Prove that \[\cos x \cos \frac{x}{2} - \cos 3x \cos\frac{9x}{2} = \sin 7x \sin 8x\]

Prove that:

\[\frac{\sin \left( \theta + \phi \right) - 2 \sin \theta + \sin \left( \theta - \phi \right)}{\cos \left( \theta + \phi \right) - 2 \cos \theta + \cos \left( \theta - \phi \right)} = \tan \theta\]

If cosec A + sec A = cosec B + sec B, prove that tan A tan B = \[\cot\frac{A + B}{2}\].


Write the value of sin \[\frac{\pi}{12}\] sin \[\frac{5\pi}{12}\].


If sin A + sin B = α and cos A + cos B = β, then write the value of tan \[\left( \frac{A + B}{2} \right)\].

 

cos 40° + cos 80° + cos 160° + cos 240° =


sin 163° cos 347° + sin 73° sin 167° =


If sin 2 θ + sin 2 ϕ = \[\frac{1}{2}\] and cos 2 θ + cos 2 ϕ = \[\frac{3}{2}\], then cos2 (θ − ϕ) =

 

 


If sin α + sin β = a and cos α − cos β = b, then tan \[\frac{\alpha - \beta}{2}\]=


cos 35° + cos 85° + cos 155° =


If cos A = m cos B, then \[\cot\frac{A + B}{2} \cot\frac{B - A}{2}\]=

 

If sin x + sin y = \[\sqrt{3}\] (cos y − cos x), then sin 3x + sin 3y =

 


Express the following as the sum or difference of sine or cosine:

`sin  "A"/8  sin  (3"A")/8`


Express the following as the product of sine and cosine.

sin A + sin 2A


Prove that:

sin A sin(60° + A) sin(60° – A) = `1/4` sin 3A


Prove that:

2 cos `pi/13` cos \[\frac{9\pi}{13} + \text{cos} \frac{3\pi}{13} + \text{cos} \frac{5\pi}{13}\] = 0


Prove that:

`(cos 7"A" +cos 5"A")/(sin 7"A" −sin 5"A")` = cot A


If tan θ = `1/sqrt5` and θ lies in the first quadrant then cos θ is:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×