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The Value of Sin 50° − Sin 70° + Sin 10° is Equal to

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Question

The value of sin 50° − sin 70° + sin 10° is equal to

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Solution

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\[\sin50^\circ - \sin70^\circ + \sin10^\circ\]
\[ = 2\sin\left( \frac{50^\circ - 70^\circ}{2} \right) \cos\left( \frac{50^\circ + 70^\circ}{2} \right) + \sin10^\circ \left[ \because \sin A - \sin B = 2\sin\left( \frac{A - B}{2} \right)\cos\left( \frac{A + B}{2} \right) \right]\]
\[ = 2\sin\left( - 10^\circ \right) \cos60^\circ + \sin10^\circ\]
\[ = 2 \times \frac{1}{2}\sin\left( - 10^\circ \right) + \sin10^\circ\]
\[ = - \sin10^\circ + \sin10^\circ\]
\[ = 0\]

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Transformation Formulae
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Chapter 8: Transformation formulae - Exercise 8.4 [Page 21]

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R.D. Sharma Mathematics [English] Class 11
Chapter 8 Transformation formulae
Exercise 8.4 | Q 8 | Page 21

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