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Prove that 4 Cos X Cos ( π 3 + X ) Cos ( π 3 − X ) = Cos 3 X .

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Question

\[\text{ Prove that }4 \cos x \cos\left( \frac{\pi}{3} + x \right) \cos \left( \frac{\pi}{3} - x \right) = \cos 3x .\]

 

Sum
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Solution

\[\text{ LHS }= 4\cos x \cos \left( \frac{\pi}{3} + x \right) \cos \left( \frac{\pi}{3} - x \right)\]
\[ = 2\cos x\left[ 2 \cos \left( \frac{\pi}{3} + x \right) \cos \left( \frac{\pi}{3} - x \right) \right]\]
\[ = 2\cos x\left[ \cos \left( \frac{\pi}{3} + x + \frac{\pi}{3} - x \right) + \cos \left( \frac{\pi}{3} + x - \frac{\pi}{3} + 2x \right) \right] \left[ \because 2\cos A \cos B = \cos (A + B) + \cos (A - B) \right]\]
\[ = 2\cos x\left[ \cos \frac{2\pi}{3} + \cos 2x \right]\]
\[ = 2\cos x\left[ - \frac{1}{2} + \cos 2x \right]\]
\[ = - \cos x + 2\cos x \cos 2x\]
\[ = - \cos x + \cos \left( x + 2x \right) + \cos \left( x - 2x \right)\]
\[ = - \cos x + \cos 3x + \cos\left( - x \right)\]
\[ = - \cos x + \cos 3x + \cos x\]
\[ = \cos 3x\]
\[\text{ RHS }= \cos 3x\]
Hence, LHS = RHS

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Transformation Formulae
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Chapter 8: Transformation formulae - Exercise 8.1 [Page 7]

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R.D. Sharma Mathematics [English] Class 11
Chapter 8 Transformation formulae
Exercise 8.1 | Q 4 | Page 7

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