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Prove That: Sin 50° + Sin 10° = Cos 20° - Mathematics

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Question

Prove that:
sin 50° + sin 10° = cos 20°

Sum
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Solution

Consider LHS: 
\[\sin 50^\circ + \sin 10^\circ\]
\[ = 2\sin \left( \frac{50^\circ + 10^\circ}{2} \right) \cos \left( \frac{50^\circ - 10^\circ}{2} \right) \left\{ \because \sin A + \sin B = 2\sin \left( \frac{A + B}{2} \right) \cos \left( \frac{A - B}{2} \right) \right\}\]
\[ = 2\sin 30^\circ \cos 20^\circ\]
\[ = 2 \times \frac{1}{2}\cos 20^\circ\]
\[ = \cos 20^\circ\]
Hence, LHS = RHS .

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Transformation Formulae
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Chapter 8: Transformation formulae - Exercise 8.2 [Page 17]

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RD Sharma Mathematics [English] Class 11
Chapter 8 Transformation formulae
Exercise 8.2 | Q 2.3 | Page 17

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