English

Sin 163° Cos 347° + Sin 73° Sin 167° =

Advertisements
Advertisements

Question

sin 163° cos 347° + sin 73° sin 167° =

Options

  • 0

  • \[\frac{1}{2}\]

     

  • 1

  • None of these

MCQ
Advertisements

Solution

\[\frac{1}{2}\]

\[\sin163^\circ\cos347^\circ + \sin73^\circ\sin167^\circ\]
\[ = \sin\left( 180^\circ - 17^\circ \right)\cos\left( 360^\circ - 13^\circ \right) + \sin\left( 90^\circ - 17^\circ \right)\sin\left( 180^\circ - 13^\circ \right)\]
\[ = \sin17^\circ\cos13^\circ + \cos17^\circ\sin13^\circ\]
\[ = \sin\left( 17^\circ + 13^\circ \right) \left[ \sin\left( A + B \right) = \sin A\cos B + \sin B\cos A \right]\]
\[ = \sin30^\circ\]
\[ = \frac{1}{2}\]

shaalaa.com
Transformation Formulae
  Is there an error in this question or solution?
Chapter 8: Transformation formulae - Exercise 8.4 [Page 21]

APPEARS IN

R.D. Sharma Mathematics [English] Class 11
Chapter 8 Transformation formulae
Exercise 8.4 | Q 2 | Page 21

RELATED QUESTIONS

Prove that: 

\[2\sin\frac{5\pi}{12}\cos\frac{\pi}{12} = \frac{\sqrt{3} + 2}{2}\]

Show that :

\[\sin 25^\circ \cos 115^\circ = \frac{1}{2}\left( \sin 140^\circ - 1 \right)\]

Prove that:
cos 40° cos 80° cos 160° = \[- \frac{1}{8}\]

 


Prove that:
\[\tan x \tan \left( \frac{\pi}{3} - x \right) \tan \left( \frac{\pi}{3} + x \right) = \tan 3x\]


If α + β = \[\frac{\pi}{2}\], show that the maximum value of cos α cos β is \[\frac{1}{2}\].

 

 


Express each of the following as the product of sines and cosines:
sin 12x + sin 4x


Express each of the following as the product of sines and cosines:
sin 5x − sin x


Express each of the following as the product of sines and cosines:
sin 2x + cos 4x


Prove that:
 sin 23° + sin 37° = cos 7°


Prove that:
sin 40° + sin 20° = cos 10°


Prove that:
sin 47° + cos 77° = cos 17°


Prove that:
sin 3A + sin 2A − sin A = 4 sin A cos \[\frac{A}{2}\] \[\frac{3A}{2}\]

 


Prove that:

\[\frac{\sin A + \sin 3A + \sin 5A}{\cos A + \cos 3A + \cos 5A} = \tan 3A\]

 


Prove that:

\[\frac{\sin 3A + \sin 5A + \sin 7A + \sin 9A}{\cos 3A + \cos 5A + \cos 7A + \cos 9A} = \tan 6A\]

Prove that:

\[\frac{\sin 3A \cos 4A - \sin A \cos 2A}{\sin 4A \sin A + \cos 6A \cos A} = \tan 2A\]

Prove that:

\[\sin \alpha + \sin \beta + \sin \gamma - \sin (\alpha + \beta + \gamma) = 4 \sin \left( \frac{\alpha + \beta}{2} \right) \sin \left( \frac{\beta + \gamma}{2} \right) \sin \left( \frac{\gamma + \alpha}{2} \right)\]

 


\[\text{ If }\frac{\cos (A - B)}{\cos (A + B)} + \frac{\cos (C + D)}{\cos (C - D)} = 0, \text {Prove that }\tan A \tan B \tan C \tan D = - 1\]

 


If cos (α + β) sin (γ + δ) = cos (α − β) sin (γ − δ), prove that cot α cot β cot γ = cot δ

 

If \[x \cos\theta = y \cos\left( \theta + \frac{2\pi}{3} \right) = z \cos\left( \theta + \frac{4\pi}{3} \right)\], prove that \[xy + yz + zx = 0\]

 

 


If sin A + sin B = α and cos A + cos B = β, then write the value of tan \[\left( \frac{A + B}{2} \right)\].

 

Write the value of \[\frac{\sin A + \sin 3A}{\cos A + \cos 3A}\]


If cos (A + B) sin (C − D) = cos (A − B) sin (C + D), then write the value of tan A tan B tan C.


If sin 2 θ + sin 2 ϕ = \[\frac{1}{2}\] and cos 2 θ + cos 2 ϕ = \[\frac{3}{2}\], then cos2 (θ − ϕ) =

 

 


The value of cos 52° + cos 68° + cos 172° is


sin 47° + sin 61° − sin 11° − sin 25° is equal to


If A, B, C are in A.P., then \[\frac{\sin A - \sin C}{\cos C - \cos A}\]=

 

If sin (B + C − A), sin (C + A − B), sin (A + B − C) are in A.P., then cot A, cot B and cot Care in


If sin x + sin y = \[\sqrt{3}\] (cos y − cos x), then sin 3x + sin 3y =

 


Express the following as the sum or difference of sine or cosine:

cos(60° + A) sin(120° + A)


Express the following as the product of sine and cosine.

cos 2A + cos 4A


Prove that:

2 cos `pi/13` cos \[\frac{9\pi}{13} + \text{cos} \frac{3\pi}{13} + \text{cos} \frac{5\pi}{13}\] = 0


Prove that:

`(cos 2"A" - cos 3"A")/(sin "2A" + sin "3A") = tan  "A"/2`


Evaluate-

cos 20° + cos 100° + cos 140°


Evaluate:

sin 50° – sin 70° + sin 10°


Find the value of tan22°30′. `["Hint:"  "Let" θ = 45°, "use" tan  theta/2 = (sin  theta/2)/(cos  theta/2) = (2sin  theta/2 cos  theta/2)/(2cos^2  theta/2) = sintheta/(1 + costheta)]`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×