मराठी

Sin 163° Cos 347° + Sin 73° Sin 167° =

Advertisements
Advertisements

प्रश्न

sin 163° cos 347° + sin 73° sin 167° =

पर्याय

  • 0

  • \[\frac{1}{2}\]

     

  • 1

  • None of these

MCQ
Advertisements

उत्तर

\[\frac{1}{2}\]

\[\sin163^\circ\cos347^\circ + \sin73^\circ\sin167^\circ\]
\[ = \sin\left( 180^\circ - 17^\circ \right)\cos\left( 360^\circ - 13^\circ \right) + \sin\left( 90^\circ - 17^\circ \right)\sin\left( 180^\circ - 13^\circ \right)\]
\[ = \sin17^\circ\cos13^\circ + \cos17^\circ\sin13^\circ\]
\[ = \sin\left( 17^\circ + 13^\circ \right) \left[ \sin\left( A + B \right) = \sin A\cos B + \sin B\cos A \right]\]
\[ = \sin30^\circ\]
\[ = \frac{1}{2}\]

shaalaa.com
Transformation Formulae
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Transformation formulae - Exercise 8.4 [पृष्ठ २१]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 11
पाठ 8 Transformation formulae
Exercise 8.4 | Q 2 | पृष्ठ २१

संबंधित प्रश्‍न

Prove that:
cos 40° cos 80° cos 160° = \[- \frac{1}{8}\]

 


Prove that:
 sin 20° sin 40° sin 80° = \[\frac{\sqrt{3}}{8}\]

 


Prove that tan 20° tan 30° tan 40° tan 80° = 1.


Prove that:
sin 10° sin 50° sin 60° sin 70° = \[\frac{\sqrt{3}}{16}\]

 


Show that:
sin A sin (B − C) + sin B sin (C − A) + sin C sin (A − B) = 0


Prove that:
\[\tan x \tan \left( \frac{\pi}{3} - x \right) \tan \left( \frac{\pi}{3} + x \right) = \tan 3x\]


Express each of the following as the product of sines and cosines:
 cos 12x - cos 4x


Express each of the following as the product of sines and cosines:
sin 2x + cos 4x


Prove that:
sin 50° + sin 10° = cos 20°


Prove that:
 cos 80° + cos 40° − cos 20° = 0


Prove that:

sin 51° + cos 81° = cos 21°

Prove that: 
cos A + cos 3A + cos 5A + cos 7A = 4 cos A cos 2A cos 4A


Prove that:
\[\sin\frac{x}{2}\sin\frac{7x}{2} + \sin\frac{3x}{2}\sin\frac{11x}{2} = \sin 2x \sin 5x .\]

 


Prove that:

\[\frac{\sin A + \sin 3A}{\cos A - \cos 3A} = \cot A\]

 


Prove that:

\[\frac{\sin 9A - \sin 7A}{\cos 7A - \cos 9A} = \cot 8A\]

Prove that:

\[\frac{\sin 5A - \sin 7A + \sin 8A - \sin 4A}{\cos 4A + \cos 7A - \cos 5A - \cos 8A} = \cot 6A\]

Prove that:

\[\frac{\sin 11A \sin A + \sin 7A \sin 3A}{\cos 11A \sin A + \cos 7A \sin 3A} = \tan 8A\]

Prove that:

\[\frac{\sin A + 2 \sin 3A + \sin 5A}{\sin 3A + 2 \sin 5A + \sin 7A} = \frac{\sin 3A}{\sin 5A}\]

If cosec A + sec A = cosec B + sec B, prove that tan A tan B = \[\cot\frac{A + B}{2}\].


\[\text{ If }\sin 2A = \lambda \sin 2B, \text{ prove that }\frac{\tan (A + B)}{\tan (A - B)} = \frac{\lambda + 1}{\lambda - 1}\]

 


Prove that:
 sin (B − C) cos (A − D) + sin (C − A) cos (B − D) + sin (A − B) cos (C − D) = 0


\[\text{ If }\frac{\cos (A - B)}{\cos (A + B)} + \frac{\cos (C + D)}{\cos (C - D)} = 0, \text {Prove that }\tan A \tan B \tan C \tan D = - 1\]

 


If cos (α + β) sin (γ + δ) = cos (α − β) sin (γ − δ), prove that cot α cot β cot γ = cot δ

 

If \[x \cos\theta = y \cos\left( \theta + \frac{2\pi}{3} \right) = z \cos\left( \theta + \frac{4\pi}{3} \right)\], prove that \[xy + yz + zx = 0\]

 

 


If cos A = m cos B, then write the value of \[\cot\frac{A + B}{2} \cot\frac{A - B}{2}\].

 

If A + B = \[\frac{\pi}{3}\] and cos A + cos B = 1, then find the value of cos \[\frac{A - B}{2}\].

 

 


If sin 2A = λ sin 2B, then write the value of \[\frac{\lambda + 1}{\lambda - 1}\]


Write the value of \[\frac{\sin A + \sin 3A}{\cos A + \cos 3A}\]


The value of cos 52° + cos 68° + cos 172° is


The value of sin 78° − sin 66° − sin 42° + sin 60° is ______.


If cos A = m cos B, then \[\cot\frac{A + B}{2} \cot\frac{B - A}{2}\]=

 

Express the following as the sum or difference of sine or cosine:

cos(60° + A) sin(120° + A)


Express the following as the sum or difference of sine or cosine:

cos 7θ sin 3θ


Express the following as the product of sine and cosine.

cos 2A + cos 4A


Prove that:

sin (A – B) sin C + sin (B – C) sin A + sin(C – A) sin B = 0


Evaluate-

cos 20° + cos 100° + cos 140°


If cos A + cos B = `1/2` and sin A + sin B = `1/4`, prove that tan `(("A + B")/2) = 1/2`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×