मराठी

Cos 40° + Cos 80° + Cos 160° + Cos 240° = - Mathematics

Advertisements
Advertisements

प्रश्न

cos 40° + cos 80° + cos 160° + cos 240° =

पर्याय

  • 0

  • 1

  • \[\frac{1}{2}\]

     

  • \[- \frac{1}{2}\]

     

MCQ
बेरीज
Advertisements

उत्तर

\[- \frac{1}{2}\]

\[\cos40^\circ + \cos80^\circ + \cos160^\circ + \cos240^\circ\]
\[ = 2\cos\left( \frac{40^\circ + 80^\circ}{2} \right)\cos\left( \frac{40^\circ - 80^\circ}{2} \right) + \cos160^\circ - \cos\left( 180^\circ + 60^\circ \right) \left[ \because \cos A + \cos B = 2\cos\left( \frac{A + B}{2} \right)\cos\left( \frac{A - B}{2} \right) \right]\]
\[ = 2\cos60^\circ \cos\left( - 20^\circ \right) + \cos160^\circ - \frac{1}{2}\]
\[ = 2 \times \frac{1}{2}\cos20^\circ + \cos160^\circ - \frac{1}{2}\]
\[ = - \cos\left( 180 - 20 \right)^\circ + \cos160^\circ - \frac{1}{2}\]
\[ = - \frac{1}{2}\]

shaalaa.com
Transformation Formulae
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Transformation formulae - Exercise 8.4 [पृष्ठ २१]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 11
पाठ 8 Transformation formulae
Exercise 8.4 | Q 1 | पृष्ठ २१

संबंधित प्रश्‍न

Prove that:
tan 20° tan 40° tan 60° tan 80° = 3

 


Prove that tan 20° tan 30° tan 40° tan 80° = 1.


Prove that:
sin 10° sin 50° sin 60° sin 70° = \[\frac{\sqrt{3}}{16}\]

 


Show that:
sin A sin (B − C) + sin B sin (C − A) + sin C sin (A − B) = 0


Express each of the following as the product of sines and cosines:
sin 12x + sin 4x


Express each of the following as the product of sines and cosines:
 cos 12x + cos 8x


Express each of the following as the product of sines and cosines:
 cos 12x - cos 4x


Express each of the following as the product of sines and cosines:
sin 2x + cos 4x


Prove that:
 cos 55° + cos 65° + cos 175° = 0


Prove that:
\[\sin\frac{5\pi}{18} - \cos\frac{4\pi}{9} = \sqrt{3} \sin\frac{\pi}{9}\]


Prove that:

\[\cos\frac{\pi}{12} - \sin\frac{\pi}{12} = \frac{1}{\sqrt{2}}\]

 


Prove that:

sin 80° − cos 70° = cos 50°

Prove that:

sin 51° + cos 81° = cos 21°

Prove that:

\[\cos\left( \frac{\pi}{4} + x \right) + \cos\left( \frac{\pi}{4} - x \right) = \sqrt{2} \cos x\]

 


Prove that:
sin 47° + cos 77° = cos 17°


Prove that:

\[\frac{\sin A + \sin B}{\sin A - \sin B} = \tan \left( \frac{A + B}{2} \right) \cot \left( \frac{A - B}{2} \right)\]

Prove that:

\[\frac{\sin 3A + \sin 5A + \sin 7A + \sin 9A}{\cos 3A + \cos 5A + \cos 7A + \cos 9A} = \tan 6A\]

Prove that:

\[\frac{\sin 3A \cos 4A - \sin A \cos 2A}{\sin 4A \sin A + \cos 6A \cos A} = \tan 2A\]

Prove that:

\[\frac{\sin A \sin 2A + \sin 3A \sin 6A}{\sin A \cos 2A + \sin 3A \cos 6A} = \tan 5A\]

Prove that:
cos (A + B + C) + cos (A − B + C) + cos (A + B − C) + cos (− A + B + C) = 4 cos A cos Bcos C


Prove that:

\[\frac{\cos (A + B + C) + \cos ( - A + B + C) + \cos (A - B + C) + \cos (A + B - C)}{\sin (A + B + C) + \sin ( - A + B + C) + \sin (A - B + C) - \sin (A + B - C)} = \cot C\]

If A + B = \[\frac{\pi}{3}\] and cos A + cos B = 1, then find the value of cos \[\frac{A - B}{2}\].

 

 


sin 163° cos 347° + sin 73° sin 167° =


The value of cos 52° + cos 68° + cos 172° is


The value of sin 50° − sin 70° + sin 10° is equal to


If cos A = m cos B, then \[\cot\frac{A + B}{2} \cot\frac{B - A}{2}\]=

 

If A, B, C are in A.P., then \[\frac{\sin A - \sin C}{\cos C - \cos A}\]=

 

Express the following as the sum or difference of sine or cosine:

`sin  "A"/8  sin  (3"A")/8`


Express the following as the sum or difference of sine or cosine:

cos 7θ sin 3θ


Express the following as the product of sine and cosine.

sin 6θ – sin 2θ


Prove that:

tan 20° tan 40° tan 80° = `sqrt3`.


Prove that:

2 cos `pi/13` cos \[\frac{9\pi}{13} + \text{cos} \frac{3\pi}{13} + \text{cos} \frac{5\pi}{13}\] = 0


Prove that cos 20° cos 40° cos 60° cos 80° = `3/16`.


If cos A + cos B = `1/2` and sin A + sin B = `1/4`, prove that tan `(("A + B")/2) = 1/2`


If sin(y + z – x), sin(z + x – y), sin(x + y – z) are in A.P, then prove that tan x, tan y and tan z are in A.P.


If secx cos5x + 1 = 0, where 0 < x ≤ `pi/2`, then find the value of x.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×