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Cos 35° + Cos 85° + Cos 155° =

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प्रश्न

cos 35° + cos 85° + cos 155° =

पर्याय

  • 0

  • \[\frac{1}{\sqrt{3}}\]

     

  • \[\frac{1}{\sqrt{2}}\]

     

  •  cos 275°

MCQ
बेरीज
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उत्तर

0

\[\cos35^\circ + \cos85^\circ + \cos155^\circ\]
\[ = 2\cos\left( \frac{35^\circ + 85^\circ}{2} \right) \cos\left( \frac{35^\circ - 85^\circ}{2} \right) + \cos155^\circ \left[ \because \cos A + \cos B = 2\cos\left( \frac{A + B}{2} \right)\cos\left( \frac{A - B}{2} \right) \right]\]
\[ = 2\cos60^\circ \cos\left( - 25^\circ \right) + \cos155^\circ\]
\[ = 2 \times \frac{1}{2}\cos25^\circ + \cos155^\circ\]
\[ = \cos25^\circ + \cos155^\circ\]
\[ = 2\cos\left( \frac{25^\circ + 155^\circ}{2} \right) \cos\left( \frac{25^\circ - 155^\circ}{2} \right)\]
\[ = 2\cos90^\circ \cos65^\circ\]
\[ = 0\]
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Transformation Formulae
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पाठ 8: Transformation formulae - Exercise 8.4 [पृष्ठ २१]

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आर.डी. शर्मा Mathematics [English] Class 11
पाठ 8 Transformation formulae
Exercise 8.4 | Q 7 | पृष्ठ २१

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