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Prove That: 2 Sin 5 π 12 Sin π 12 = 1 2 - Mathematics

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प्रश्न

Prove that:

\[2\sin\frac{5\pi}{12}\sin\frac{\pi}{12} = \frac{1}{2}\]

 

बेरीज
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उत्तर

\[LHS = 2\left( \sin \frac{5\pi}{12} \right) \left( \sin \frac{\pi}{12} \right)\]
\[ = \cos \left( \frac{5\pi}{12} - \frac{\pi}{12} \right) - \cos \left( \frac{5\pi}{12} + \frac{\pi}{12} \right) \left[ \because 2 \sin A \sin B = \cos (A - B) - \cos (A + B) \right]\]
\[ = \cos \frac{\pi}{3} - \cos \frac{\pi}{2}\]
\[ = \frac{1}{2} - 0\]
\[ = \frac{1}{2}\]
\[RHS = \frac{1}{2}\]
Hence, LHS = RHS

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Transformation Formulae
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पाठ 8: Transformation formulae - Exercise 8.1 [पृष्ठ ६]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 8 Transformation formulae
Exercise 8.1 | Q 2.1 | पृष्ठ ६

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