मराठी

The value of sin 78° − sin 66° − sin 42° + sin 60° is

Advertisements
Advertisements

प्रश्न

The value of sin 78° − sin 66° − sin 42° + sin 60° is ______.

पर्याय

  • \[\frac{1}{2}\]

     

  • \[- \frac{1}{2}\]

     

  • −1

  • None of these

MCQ
रिकाम्या जागा भरा
Advertisements

उत्तर

None of these

Explanation:

= \[\sin78^\circ - \sin66^\circ - \sin42^\circ + \sin60^\circ\]

\[ = \sin78^\circ - \sin42^\circ - \sin66^\circ + \sin60^\circ\]

\[ = 2\sin\left( \frac{78^\circ - 42^\circ}{2} \right)\cos\left( \frac{78^\circ + 42}{2} \right) - \sin66^\circ + \sin60^\circ \left[ \because \sin A - \sin B = 2\sin\left( \frac{A - B}{2} \right)\cos\left( \frac{A + B}{2} \right) \right]\]

\[ = 2\sin18^\circ \cos60^\circ - \sin66^\circ + \sin60^\circ\]

\[ = 2 \times \frac{1}{2}\sin18^\circ - \sin66^\circ + \frac{\sqrt{3}}{2}\]

\[ = \sin18^\circ - \sin66^\circ + \frac{\sqrt{3}}{2}\]

\[ = \frac{\sqrt{5} - 1}{4} - 0 . 914 + \frac{\sqrt{3}}{2}\]

= 0.309 − 0.914 + 0.866

= 0.261

shaalaa.com
Transformation Formulae
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Transformation formulae - Exercise 8.4 [पृष्ठ २१]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 11
पाठ 8 Transformation formulae
Exercise 8.4 | Q 5 | पृष्ठ २१

संबंधित प्रश्‍न

Prove that:

\[2\sin\frac{5\pi}{12}\sin\frac{\pi}{12} = \frac{1}{2}\]

 


Prove that:
cos 10° cos 30° cos 50° cos 70° = \[\frac{3}{16}\]


Prove that:
tan 20° tan 40° tan 60° tan 80° = 3

 


Prove that tan 20° tan 30° tan 40° tan 80° = 1.


Show that:
sin (B − C) cos (A − D) + sin (C − A) cos (B − D) + sin (A − B) cos (C − D) = 0


Prove that:
\[\tan x \tan \left( \frac{\pi}{3} - x \right) \tan \left( \frac{\pi}{3} + x \right) = \tan 3x\]


Prove that:
sin 38° + sin 22° = sin 82°


Prove that:
sin 105° + cos 105° = cos 45°


Prove that:
 cos 55° + cos 65° + cos 175° = 0


Prove that:
 cos 80° + cos 40° − cos 20° = 0


Prove that:
\[\sin\frac{5\pi}{18} - \cos\frac{4\pi}{9} = \sqrt{3} \sin\frac{\pi}{9}\]


Prove that:

sin 80° − cos 70° = cos 50°

Prove that \[\cos x \cos \frac{x}{2} - \cos 3x \cos\frac{9x}{2} = \sin 7x \sin 8x\]

Prove that:

\[\frac{\sin 9A - \sin 7A}{\cos 7A - \cos 9A} = \cot 8A\]

Prove that:

\[\frac{\sin A + \sin 3A + \sin 5A}{\cos A + \cos 3A + \cos 5A} = \tan 3A\]

 


Prove that:

\[\frac{\sin 5A \cos 2A - \sin 6A \cos A}{\sin A \sin 2A - \cos 2A \cos 3A} = \tan A\]

Prove that:

\[\frac{\sin \left( \theta + \phi \right) - 2 \sin \theta + \sin \left( \theta - \phi \right)}{\cos \left( \theta + \phi \right) - 2 \cos \theta + \cos \left( \theta - \phi \right)} = \tan \theta\]

If cosec A + sec A = cosec B + sec B, prove that tan A tan B = \[\cot\frac{A + B}{2}\].


\[\text{ If }\sin 2A = \lambda \sin 2B, \text{ prove that }\frac{\tan (A + B)}{\tan (A - B)} = \frac{\lambda + 1}{\lambda - 1}\]

 


Write the value of sin \[\frac{\pi}{12}\] sin \[\frac{5\pi}{12}\].


If cos A = m cos B, then write the value of \[\cot\frac{A + B}{2} \cot\frac{A - B}{2}\].

 

Write the value of the expression \[\frac{1 - 4 \sin 10^\circ \sin 70^\circ}{2 \sin 10^\circ}\]


If sin 2A = λ sin 2B, then write the value of \[\frac{\lambda + 1}{\lambda - 1}\]


If cos (A + B) sin (C − D) = cos (A − B) sin (C + D), then write the value of tan A tan B tan C.


cos 40° + cos 80° + cos 160° + cos 240° =


If sin 2 θ + sin 2 ϕ = \[\frac{1}{2}\] and cos 2 θ + cos 2 ϕ = \[\frac{3}{2}\], then cos2 (θ − ϕ) =

 

 


The value of cos 52° + cos 68° + cos 172° is


If sin x + sin y = \[\sqrt{3}\] (cos y − cos x), then sin 3x + sin 3y =

 


If \[\tan\alpha = \frac{x}{x + 1}\] and 

\[\tan\beta = \frac{1}{2x + 1}\], then
\[\tan\beta = \frac{1}{2x + 1}\] is equal to

 


Express the following as the sum or difference of sine or cosine:

`cos  (7"A")/3 sin  (5"A")/3`


Express the following as the product of sine and cosine.

sin 6θ – sin 2θ


Prove that:

(cos α – cos β)2 + (sin α – sin β)2 = 4 sin2 `((alpha - beta)/2)`


Prove that cos 20° cos 40° cos 60° cos 80° = `3/16`.


If tan θ = `1/sqrt5` and θ lies in the first quadrant then cos θ is:


If secx cos5x + 1 = 0, where 0 < x ≤ `pi/2`, then find the value of x.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×