मराठी

The value of sin 78° − sin 66° − sin 42° + sin 60° is

Advertisements
Advertisements

प्रश्न

The value of sin 78° − sin 66° − sin 42° + sin 60° is ______.

पर्याय

  • \[\frac{1}{2}\]

     

  • \[- \frac{1}{2}\]

     

  • −1

  • None of these

MCQ
रिकाम्या जागा भरा
Advertisements

उत्तर

None of these

Explanation:

= \[\sin78^\circ - \sin66^\circ - \sin42^\circ + \sin60^\circ\]

\[ = \sin78^\circ - \sin42^\circ - \sin66^\circ + \sin60^\circ\]

\[ = 2\sin\left( \frac{78^\circ - 42^\circ}{2} \right)\cos\left( \frac{78^\circ + 42}{2} \right) - \sin66^\circ + \sin60^\circ \left[ \because \sin A - \sin B = 2\sin\left( \frac{A - B}{2} \right)\cos\left( \frac{A + B}{2} \right) \right]\]

\[ = 2\sin18^\circ \cos60^\circ - \sin66^\circ + \sin60^\circ\]

\[ = 2 \times \frac{1}{2}\sin18^\circ - \sin66^\circ + \frac{\sqrt{3}}{2}\]

\[ = \sin18^\circ - \sin66^\circ + \frac{\sqrt{3}}{2}\]

\[ = \frac{\sqrt{5} - 1}{4} - 0 . 914 + \frac{\sqrt{3}}{2}\]

= 0.309 − 0.914 + 0.866

= 0.261

shaalaa.com
Transformation Formulae
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Transformation formulae - Exercise 8.4 [पृष्ठ २१]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 11
पाठ 8 Transformation formulae
Exercise 8.4 | Q 5 | पृष्ठ २१

संबंधित प्रश्‍न

Prove that:

\[2\cos\frac{5\pi}{12}\cos\frac{\pi}{12} = \frac{1}{2}\]

Show that :

\[\sin 50^\circ \cos 85^\circ = \frac{1 - \sqrt{2} \sin 35^\circ}{2\sqrt{2}}\]

Show that :

\[\sin 25^\circ \cos 115^\circ = \frac{1}{2}\left( \sin 140^\circ - 1 \right)\]

Prove that:
tan 20° tan 40° tan 60° tan 80° = 3

 


Express each of the following as the product of sines and cosines:
sin 5x − sin x


Prove that:
sin 38° + sin 22° = sin 82°


Prove that:
 sin 23° + sin 37° = cos 7°


Prove that:
 cos 80° + cos 40° − cos 20° = 0


Prove that:

sin 80° − cos 70° = cos 50°

Prove that \[\cos x \cos \frac{x}{2} - \cos 3x \cos\frac{9x}{2} = \sin 7x \sin 8x\]

Prove that:

\[\frac{\sin A + \sin 3A}{\cos A - \cos 3A} = \cot A\]

 


Prove that:

\[\frac{\sin A - \sin B}{\cos A + \cos B} = \tan\frac{A - B}{2}\]

Prove that:

\[\frac{\cos 3A + 2 \cos 5A + \cos 7A}{\cos A + 2 \cos 3A + \cos 5A} = \frac{\cos 5A}{\cos 3A}\]

Prove that:

\[\frac{\sin A + \sin 3A + \sin 5A}{\cos A + \cos 3A + \cos 5A} = \tan 3A\]

 


Prove that:

\[\frac{\sin 5A \cos 2A - \sin 6A \cos A}{\sin A \sin 2A - \cos 2A \cos 3A} = \tan A\]

Prove that:

\[\frac{\sin 11A \sin A + \sin 7A \sin 3A}{\cos 11A \sin A + \cos 7A \sin 3A} = \tan 8A\]

Prove that:

\[\frac{\sin 3A \cos 4A - \sin A \cos 2A}{\sin 4A \sin A + \cos 6A \cos A} = \tan 2A\]

Prove that:

\[\frac{\sin A + 2 \sin 3A + \sin 5A}{\sin 3A + 2 \sin 5A + \sin 7A} = \frac{\sin 3A}{\sin 5A}\]

Prove that:

\[\frac{\sin \left( \theta + \phi \right) - 2 \sin \theta + \sin \left( \theta - \phi \right)}{\cos \left( \theta + \phi \right) - 2 \cos \theta + \cos \left( \theta - \phi \right)} = \tan \theta\]

\[\text{ If }\frac{\cos (A - B)}{\cos (A + B)} + \frac{\cos (C + D)}{\cos (C - D)} = 0, \text {Prove that }\tan A \tan B \tan C \tan D = - 1\]

 


If cos (α + β) sin (γ + δ) = cos (α − β) sin (γ − δ), prove that cot α cot β cot γ = cot δ

 

If A + B = \[\frac{\pi}{3}\] and cos A + cos B = 1, then find the value of cos \[\frac{A - B}{2}\].

 

 


Write the value of \[\frac{\sin A + \sin 3A}{\cos A + \cos 3A}\]


sin 47° + sin 61° − sin 11° − sin 25° is equal to


If sin (B + C − A), sin (C + A − B), sin (A + B − C) are in A.P., then cot A, cot B and cot Care in


Express the following as the sum or difference of sine or cosine:

cos(60° + A) sin(120° + A)


Express the following as the sum or difference of sine or cosine:

`cos  (7"A")/3 sin  (5"A")/3`


Express the following as the sum or difference of sine or cosine:

cos 7θ sin 3θ


Prove that:

cos 20° cos 40° cos 80° = `1/8`


Prove that:

2 cos `pi/13` cos \[\frac{9\pi}{13} + \text{cos} \frac{3\pi}{13} + \text{cos} \frac{5\pi}{13}\] = 0


Prove that:

`(cos 2"A" - cos 3"A")/(sin "2A" + sin "3A") = tan  "A"/2`


Prove that cos 20° cos 40° cos 60° cos 80° = `3/16`.


Evaluate:

sin 50° – sin 70° + sin 10°


If sin(y + z – x), sin(z + x – y), sin(x + y – z) are in A.P, then prove that tan x, tan y and tan z are in A.P.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×