मराठी

If a + B = π 3 and Cos a + Cos B = 1, Then Find the Value of Cos a − B 2 .

Advertisements
Advertisements

प्रश्न

If A + B = \[\frac{\pi}{3}\] and cos A + cos B = 1, then find the value of cos \[\frac{A - B}{2}\].

 

 

बेरीज
Advertisements

उत्तर

Given:
A + B =\[\frac{\pi}{3}\] and cos A + cos B = 1
\[\Rightarrow 2\cos\left( \frac{A + B}{2} \right)\cos\left( \frac{A - B}{2} \right) = 1 \left[ \because \cos A + \cos B = 2\cos\left( \frac{A + B}{2} \right)\cos\left( \frac{A - B}{2} \right) \right]\]
\[ \Rightarrow 2\cos\left( \frac{\pi}{6} \right)\cos\left( \frac{A - B}{2} \right) = 1 \left[ \because A + B = \frac{\pi}{3} \right]\]
\[ \Rightarrow 2 \times \frac{\sqrt{3}}{2} \times \cos\left( \frac{A - B}{2} \right) = 1\]
\[ \Rightarrow \cos\left( \frac{A - B}{2} \right) = \frac{1}{\sqrt{3}}\]

shaalaa.com
Transformation Formulae
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Transformation formulae - Exercise 8.3 [पृष्ठ २०]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 11
पाठ 8 Transformation formulae
Exercise 8.3 | Q 6 | पृष्ठ २०

संबंधित प्रश्‍न

Prove that:

\[2\cos\frac{5\pi}{12}\cos\frac{\pi}{12} = \frac{1}{2}\]

Show that :

\[\sin 50^\circ \cos 85^\circ = \frac{1 - \sqrt{2} \sin 35^\circ}{2\sqrt{2}}\]

Show that :

\[\sin 25^\circ \cos 115^\circ = \frac{1}{2}\left( \sin 140^\circ - 1 \right)\]

\[\text{ Prove that }4 \cos x \cos\left( \frac{\pi}{3} + x \right) \cos \left( \frac{\pi}{3} - x \right) = \cos 3x .\]

 


Prove that:
cos 20° cos 40° cos 80° = \[\frac{1}{8}\]

 


Prove that:
tan 20° tan 40° tan 60° tan 80° = 3

 


Express each of the following as the product of sines and cosines:
sin 5x − sin x


Prove that:
 cos 100° + cos 20° = cos 40°


Prove that:
sin 50° + sin 10° = cos 20°


Prove that:

sin 51° + cos 81° = cos 21°

Prove that: 
cos A + cos 3A + cos 5A + cos 7A = 4 cos A cos 2A cos 4A


Prove that:
 `sin A + sin 2A + sin 4A + sin 5A = 4 cos (A/2) cos((3A)/2)sin3A`


Prove that:
sin 3A + sin 2A − sin A = 4 sin A cos \[\frac{A}{2}\] \[\frac{3A}{2}\]

 


Prove that:

\[\frac{\sin A + \sin 3A}{\cos A - \cos 3A} = \cot A\]

 


Prove that:

\[\frac{\sin A + \sin B}{\sin A - \sin B} = \tan \left( \frac{A + B}{2} \right) \cot \left( \frac{A - B}{2} \right)\]

Prove that:

\[\sin \alpha + \sin \beta + \sin \gamma - \sin (\alpha + \beta + \gamma) = 4 \sin \left( \frac{\alpha + \beta}{2} \right) \sin \left( \frac{\beta + \gamma}{2} \right) \sin \left( \frac{\gamma + \alpha}{2} \right)\]

 


\[\text{ If } \cos A + \cos B = \frac{1}{2}\text{ and }\sin A + \sin B = \frac{1}{4},\text{ prove that }\tan\left( \frac{A + B}{2} \right) = \frac{1}{2} .\]

 


\[\text{ If }\frac{\cos (A - B)}{\cos (A + B)} + \frac{\cos (C + D)}{\cos (C - D)} = 0, \text {Prove that }\tan A \tan B \tan C \tan D = - 1\]

 


If \[m \sin\theta = n \sin\left( \theta + 2\alpha \right)\], prove that \[\tan\left( \theta + \alpha \right) \cot\alpha = \frac{m + n}{m - n}\]


If (cos α + cos β)2 + (sin α + sin β)2 = \[\lambda \cos^2 \left( \frac{\alpha - \beta}{2} \right)\], write the value of λ. 


Write the value of sin \[\frac{\pi}{12}\] sin \[\frac{5\pi}{12}\].


If sin A + sin B = α and cos A + cos B = β, then write the value of tan \[\left( \frac{A + B}{2} \right)\].

 

Write the value of \[\sin\frac{\pi}{15}\sin\frac{4\pi}{15}\sin\frac{3\pi}{10}\]


The value of cos 52° + cos 68° + cos 172° is


The value of sin 50° − sin 70° + sin 10° is equal to


sin 47° + sin 61° − sin 11° − sin 25° is equal to


If cos A = m cos B, then \[\cot\frac{A + B}{2} \cot\frac{B - A}{2}\]=

 

Express the following as the sum or difference of sine or cosine:

cos(60° + A) sin(120° + A)


Express the following as the product of sine and cosine.

sin A + sin 2A


Prove that:

tan 20° tan 40° tan 80° = `sqrt3`.


Prove that:

(cos α – cos β)2 + (sin α – sin β)2 = 4 sin2 `((alpha - beta)/2)`


Prove that:

sin (A – B) sin C + sin (B – C) sin A + sin(C – A) sin B = 0


Prove that:

2 cos `pi/13` cos \[\frac{9\pi}{13} + \text{cos} \frac{3\pi}{13} + \text{cos} \frac{5\pi}{13}\] = 0


Evaluate-

cos 20° + cos 100° + cos 140°


If tan θ = `1/sqrt5` and θ lies in the first quadrant then cos θ is:


If secx cos5x + 1 = 0, where 0 < x ≤ `pi/2`, then find the value of x.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×