मराठी

If Sin a + Sin B = α and Cos a + Cos B = β, Then Write the Value of Tan ( a + B 2 ) .

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प्रश्न

If sin A + sin B = α and cos A + cos B = β, then write the value of tan \[\left( \frac{A + B}{2} \right)\].

 
बेरीज
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उत्तर

Given:
sin A + sin B = α            .....(i)
cos A + cos B = β           .....(ii)
Dividing (i) by (ii):

\[\Rightarrow \frac{\sin A + \sin B}{\cos A + \cos B} = \frac{\alpha}{\beta}\]

\[ \Rightarrow \frac{2\sin\left( \frac{A + B}{2} \right)\cos\left( \frac{A - B}{2} \right)}{2\cos\left( \frac{A + B}{2} \right)\cos\left( \frac{A - B}{2} \right)} = \frac{\alpha}{\beta} \left[ \because \sin A + \sin B = 2\sin\left( \frac{A + B}{2} \right)\cos\left( \frac{A - B}{2} \right)\text{ and }\cos A + \cos B = 2\cos\left( \frac{A + B}{2} \right)\cos\left( \frac{A - B}{2} \right) \right]\]

\[ \Rightarrow \frac{\sin\left( \frac{A + B}{2} \right)\cos\left( \frac{A - B}{2} \right)}{\cos\left( \frac{A + B}{2} \right)\cos\left( \frac{A - B}{2} \right)} = \frac{\alpha}{\beta}\]

\[ \Rightarrow \tan\left( \frac{A + B}{2} \right)=\frac{\alpha}{\beta}\]

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Transformation Formulae
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पाठ 8: Transformation formulae - Exercise 8.3 [पृष्ठ २०]

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आर.डी. शर्मा Mathematics [English] Class 11
पाठ 8 Transformation formulae
Exercise 8.3 | Q 3 | पृष्ठ २०

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