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Cos 40° + Cos 80° + Cos 160° + Cos 240° =

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प्रश्न

cos 40° + cos 80° + cos 160° + cos 240° =

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  • 1

  • \[\frac{1}{2}\]

     

  • \[- \frac{1}{2}\]

     

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उत्तर

\[- \frac{1}{2}\]

\[\cos40^\circ + \cos80^\circ + \cos160^\circ + \cos240^\circ\]
\[ = 2\cos\left( \frac{40^\circ + 80^\circ}{2} \right)\cos\left( \frac{40^\circ - 80^\circ}{2} \right) + \cos160^\circ - \cos\left( 180^\circ + 60^\circ \right) \left[ \because \cos A + \cos B = 2\cos\left( \frac{A + B}{2} \right)\cos\left( \frac{A - B}{2} \right) \right]\]
\[ = 2\cos60^\circ \cos\left( - 20^\circ \right) + \cos160^\circ - \frac{1}{2}\]
\[ = 2 \times \frac{1}{2}\cos20^\circ + \cos160^\circ - \frac{1}{2}\]
\[ = - \cos\left( 180 - 20 \right)^\circ + \cos160^\circ - \frac{1}{2}\]
\[ = - \frac{1}{2}\]

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Transformation Formulae
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Transformation formulae - Exercise 8.4 [पृष्ठ २१]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 8 Transformation formulae
Exercise 8.4 | Q 1 | पृष्ठ २१

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