हिंदी

Cos 40° + Cos 80° + Cos 160° + Cos 240° =

Advertisements
Advertisements

प्रश्न

cos 40° + cos 80° + cos 160° + cos 240° =

विकल्प

  • 0

  • 1

  • \[\frac{1}{2}\]

     

  • \[- \frac{1}{2}\]

     

MCQ
योग
Advertisements

उत्तर

\[- \frac{1}{2}\]

\[\cos40^\circ + \cos80^\circ + \cos160^\circ + \cos240^\circ\]
\[ = 2\cos\left( \frac{40^\circ + 80^\circ}{2} \right)\cos\left( \frac{40^\circ - 80^\circ}{2} \right) + \cos160^\circ - \cos\left( 180^\circ + 60^\circ \right) \left[ \because \cos A + \cos B = 2\cos\left( \frac{A + B}{2} \right)\cos\left( \frac{A - B}{2} \right) \right]\]
\[ = 2\cos60^\circ \cos\left( - 20^\circ \right) + \cos160^\circ - \frac{1}{2}\]
\[ = 2 \times \frac{1}{2}\cos20^\circ + \cos160^\circ - \frac{1}{2}\]
\[ = - \cos\left( 180 - 20 \right)^\circ + \cos160^\circ - \frac{1}{2}\]
\[ = - \frac{1}{2}\]

shaalaa.com
Transformation Formulae
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Transformation formulae - Exercise 8.4 [पृष्ठ २१]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 8 Transformation formulae
Exercise 8.4 | Q 1 | पृष्ठ २१

संबंधित प्रश्न

Prove that:

\[2\cos\frac{5\pi}{12}\cos\frac{\pi}{12} = \frac{1}{2}\]

Prove that:
cos 10° cos 30° cos 50° cos 70° = \[\frac{3}{16}\]


If α + β = \[\frac{\pi}{2}\], show that the maximum value of cos α cos β is \[\frac{1}{2}\].

 

 


Express each of the following as the product of sines and cosines:
sin 12x + sin 4x


Express each of the following as the product of sines and cosines:
sin 5x − sin x


Express each of the following as the product of sines and cosines:
sin 2x + cos 4x


Prove that:
sin 38° + sin 22° = sin 82°


Prove that:
sin 50° + sin 10° = cos 20°


Prove that:
\[\sin\frac{5\pi}{18} - \cos\frac{4\pi}{9} = \sqrt{3} \sin\frac{\pi}{9}\]


Prove that:

sin 51° + cos 81° = cos 21°

Prove that:

\[\cos\left( \frac{3\pi}{4} + x \right) - \cos\left( \frac{3\pi}{4} - x \right) = - \sqrt{2} \sin x\]

 


Prove that:

\[\sin 65^\circ + \cos 65^\circ = \sqrt{2} \cos 20^\circ\]

Prove that:
 `sin A + sin 2A + sin 4A + sin 5A = 4 cos (A/2) cos((3A)/2)sin3A`


Prove that:
sin 3A + sin 2A − sin A = 4 sin A cos \[\frac{A}{2}\] \[\frac{3A}{2}\]

 


Prove that:

\[\frac{\sin A + \sin 3A}{\cos A - \cos 3A} = \cot A\]

 


Prove that:

\[\frac{\cos 3A + 2 \cos 5A + \cos 7A}{\cos A + 2 \cos 3A + \cos 5A} = \frac{\cos 5A}{\cos 3A}\]

Prove that:

\[\frac{\cos 4A + \cos 3A + \cos 2A}{\sin 4A + \sin 3A + \sin 2A} = \cot 3A\]

 


Prove that:

\[\frac{\sin A + 2 \sin 3A + \sin 5A}{\sin 3A + 2 \sin 5A + \sin 7A} = \frac{\sin 3A}{\sin 5A}\]

Prove that:

\[\sin \alpha + \sin \beta + \sin \gamma - \sin (\alpha + \beta + \gamma) = 4 \sin \left( \frac{\alpha + \beta}{2} \right) \sin \left( \frac{\beta + \gamma}{2} \right) \sin \left( \frac{\gamma + \alpha}{2} \right)\]

 


Prove that:
cos (A + B + C) + cos (A − B + C) + cos (A + B − C) + cos (− A + B + C) = 4 cos A cos Bcos C


\[\text{ If }\sin 2A = \lambda \sin 2B, \text{ prove that }\frac{\tan (A + B)}{\tan (A - B)} = \frac{\lambda + 1}{\lambda - 1}\]

 


If cos (A + B) sin (C − D) = cos (A − B) sin (C + D), prove that tan A tan B tan C + tan D = 0.

 

If cos A = m cos B, then write the value of \[\cot\frac{A + B}{2} \cot\frac{A - B}{2}\].

 

sin 163° cos 347° + sin 73° sin 167° =


The value of sin 78° − sin 66° − sin 42° + sin 60° is ______.


The value of sin 50° − sin 70° + sin 10° is equal to


sin 47° + sin 61° − sin 11° − sin 25° is equal to


If sin (B + C − A), sin (C + A − B), sin (A + B − C) are in A.P., then cot A, cot B and cot Care in


If \[\tan\alpha = \frac{x}{x + 1}\] and 

\[\tan\beta = \frac{1}{2x + 1}\], then
\[\tan\beta = \frac{1}{2x + 1}\] is equal to

 


Express the following as the product of sine and cosine.

cos 2A + cos 4A


Prove that:

tan 20° tan 40° tan 80° = `sqrt3`.


Evaluate-

cos 20° + cos 100° + cos 140°


Evaluate:

sin 50° – sin 70° + sin 10°


If sin(y + z – x), sin(z + x – y), sin(x + y – z) are in A.P, then prove that tan x, tan y and tan z are in A.P.


If secx cos5x + 1 = 0, where 0 < x ≤ `pi/2`, then find the value of x.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×