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Question
Let z1 = 2 – i, z2 = –2 + i. Find `"Im"(1/(z_1barz_1))`
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Solution
`1/(z_1z_1) = 1/((2 - i)(2-i)) = 1/((2- i)(2 + i))`
= `1/(4 - i^2) = 1/5`
∴ `"Im"(1/(z_1barz_1))` = 0
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