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Question
Find a and b if a + 2b + 2ai = 4 + 6i
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Solution
a + 2b + 2ai = 4 + 6i
Equating real and imaginary parts, we get
a + 2b = 4 …(i)
2a = 6 …(ii)
∴ a = 3
Substituting, a = 3 in (i), we get
3 + 2b = 4
∴ b = `1/2`
∴ a = 3 and b = `1/2`
For a = 3 and b = `1/2`
Consider L.H.S. = a + 2b + 2ai
= `3 + 2(1/2) + 2(3)i`
= 4 + 6i
= R.H.S.
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