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The Amplitude of 1 + I √ 3 √ 3 + I is - Mathematics

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Question

The amplitude of \[\frac{1 + i\sqrt{3}}{\sqrt{3} + i}\] is 

Options

  • \[\frac{\pi}{3}\]

  • \[- \frac{\pi}{3}\]

  • \[\frac{\pi}{6}\]

  • \[- \frac{\pi}{6}\]

MCQ
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Solution

\[\frac{\pi}{6}\]

\[\text { Let }z = \frac{1 + i\sqrt{3}}{\sqrt{3} + i}\]

\[ \Rightarrow z=\frac{1 + i\sqrt{3}}{\sqrt{3} + i}\times\frac{\sqrt{3} - i}{\sqrt{3} - i}\]

\[ \Rightarrow z=\frac{\sqrt{3} + 2i - \sqrt{3} i^2}{3 - i^2}\]

\[ \Rightarrow z=\frac{\sqrt{3} + \sqrt{3} + 2i}{4}\]

\[ \Rightarrow z = \frac{2\sqrt{3} + 2i}{4}\]

\[ \Rightarrow z = \frac{\sqrt{3}}{2} + \frac{1}{2}i\]

\[\tan \alpha = \left| \frac{Im(z)}{Re(z)} \right|\]

\[ = \frac{1}{\sqrt{3}}\]

\[ \Rightarrow \alpha = \frac{\pi}{6}\]

\[\text { Since, z lies in the first quadrant } . \]

\[\text{Therefore,} arg(z)=\tan^{- 1}\left( \frac{1}{\sqrt{3}} \right)=\frac{\pi}{6}\]

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Chapter 13: Complex Numbers - Exercise 13.6 [Page 66]

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RD Sharma Mathematics [English] Class 11
Chapter 13 Complex Numbers
Exercise 13.6 | Q 32 | Page 66

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