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Let A = [23-12]. Then show that A2 – 4A + 7I = O. Using this result calculate A5 also. - Mathematics

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Question

Let A = `[(2, 3),(-1, 2)]`. Then show that A2 – 4A + 7I = O. Using this result calculate A5 also.

Sum
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Solution

We have A2 = `[(2, 3),(-1, 2)] [(2, 3),(-1, 2)] = [(1, 12),(-4, 1)]`

– 4A = `[(-8, -12),(4, -8)]` and 7I = `[(7, 0),(0, 7)]`

Therefore, A2 – 4A + 7I = `[(1 - 8 + 7, 12 - 12 + 0),(-4 + 4 + 0, 1 - 8 + 7)]`

= `[(0, 0),(0, 0)]`

= O

⇒ A2 – 4A + 7I

Thus A3 = A.A2 = A(4A – 7I)

= 4(4A – 7I) – 7A

= 16A – 28I – 7A = 9A – 28I

and so A5 = A3A2

= (9A – 28I) (4A – 7I)

= 36A2 – 63A – 112A + 196I

= 36(4A – 7I) – 175A + 196I

= – 31A – 56I

= `-3"I"[(2, 3),(-1, 2)] -56[(1, 0),(0, 1)]`

= `[(-118, -93),(31, -118)]`

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Chapter 3: Matrices - Solved Examples [Page 50]

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NCERT Exemplar Mathematics [English] Class 12
Chapter 3 Matrices
Solved Examples | Q 8 | Page 50

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