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Question
In a triangle, an exterior angle at a vertex is 95° and its one of the interior opposite angle is 55°, then the measure of the other interior angle is
Options
55°
85°
40°
9.0°
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Solution
In the given ΔABC, ∠DAC = 95° and ∠A = 55°
Now, according to the property, “exterior angle of a triangle is equal to the sum of two opposite interior angles”, we get,
∠A + ∠B = ∠ACD
55° + ∠B = 95°
∠B = 95° - 55°
= 40°
So, ∠B = 40°
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