Advertisements
Advertisements
Question
In a triangle, an exterior angle at a vertex is 95° and its one of the interior opposite angle is 55°, then the measure of the other interior angle is
Options
55°
85°
40°
9.0°
Advertisements
Solution
In the given ΔABC, ∠DAC = 95° and ∠A = 55°
Now, according to the property, “exterior angle of a triangle is equal to the sum of two opposite interior angles”, we get,
∠A + ∠B = ∠ACD
55° + ∠B = 95°
∠B = 95° - 55°
= 40°
So, ∠B = 40°
APPEARS IN
RELATED QUESTIONS
The bisectors of base angles of a triangle cannot enclose a right angle in any case.
If each angle of a triangle is less than the sum of the other two, show that the triangle is acute angled.
In Fig. 10.25, AB = AC and DB = DC, find the ratio ∠ABD : ∠ACD.
Compute the value of x in the following figure:
Is the following statement true and false :
An exterior angle of a triangle is greater than the opposite interior angles.
Fill in the blank to make the following statement true:
A triangle cannot have more than ...... right angles.
In the given figure, AM ⊥ BC and AN is the bisector of ∠A. If ∠B = 65° and ∠C = 33°, find ∠MAN.
The angle of a vertex of an isosceles triangle is 100°. Find its base angles.
O is a point in the interior of a square ABCD such that OAB is an equilateral triangle. Show that ∆OCD is an isosceles triangle.
Can we have two acute angles whose sum is an obtuse angle? Why or why not?
