Advertisements
Advertisements
Question
If each angle of a triangle is less than the sum of the other two, show that the triangle is acute angled.
Advertisements
Solution
Given each angle of a triangle less than the sum of the other two
`∴∠A+∠ B+∠C`
`⇒∠A+∠A<∠A+∠B+∠C`
`⇒2∠A<180^@`
[Sum of all angles of a triangle]
`⇒∠A<90^@`
Similarly` ∠ B< 90^@ and ∠C<90^@`
Hence, the triangles acute angled.
APPEARS IN
RELATED QUESTIONS
The angles of a triangle are (x − 40)°, (x − 20)° and `(1/2x-10)^@.` find the value of x
Two angles of a triangle are equal and the third angle is greater than each of those angles
by 30°. Determine all the angles of the triangle.
Can a triangle have two acute angles?Justify your answer in case.
Calculate the angles of a triangle if they are in the ratio 4: 5: 6.
In the following, find the marked unknown angle:

Find x, if the angles of a triangle is:
2x°, 4x°, 6x°
In ∆ABC, ∠A = ∠B = 62° ; find ∠C.
Classify the following triangle according to angle:

In the following figure, AD is the bisector of ∠BAC. Prove that AB > BD.

In the following figure, points lying in the interior of the triangle PQR are ______, that in the exterior are ______ and that on the triangle itself are ______.

